java-jmu-m02-寻找包含密码的字符串

king
3
The king is coming!
Where is he now?
He's in the kingdom.
Are you sure?
!!!kingnevertelllie!!!
king is the king
end

1 The king is coming!
3 He's in the kingdom.
5 !!!kingnevertelllie!!!
3

java
3
Do you like coffe?
Yes, i like java.
java is also my favorite
King don't love coffe.
king is the king
end

R7-20 java-jmu-m02-寻找包含密码的字符串 (25 分)
输入密码x与次数n。然后在若干行字符串中(以end为结尾)寻找包含指定密码（x）的字符串的。
一旦找到就输出该字符串所在行数及该行字符串 。 最后输出包含密码x的字符串行数。
在寻找过程中，如果找到n次包含密码x的字符串则直接跳出循环，否则一直查找直到碰到end为止。
输入格式:
输入密码x
输入次数n
输入若干字符串以end结束
输出格式:
该字符串所在行数及包含密码x的字符串
符合条件的字符串出现的次数
输入样例1:
king
3
The king is coming!
Where is he now?
He's in the kingdom.
Are you sure?
!!!kingnevertelllie!!!
king is the king
end
输出样例1:
1 The king is coming!
3 He's in the kingdom.
5 !!!kingnevertelllie!!!
3
输入样例2:
java
3
Do you like coffe?
Yes, i like java.
java is also my favorite
King don't love coffe.
king is the king
end
输出样例2:
2 Yes, i like java.
3 java is also my favorite
2
import java.util.Scanner;
public class J_20 {
  public static void main(String[] args) {
    @SuppressWarnings("resource")
    Scanner sc=new Scanner(System.in);
    String x=sc.nextLine();
    int n=sc.nextInt();
    String str;
    int hang=-1,count=0,i=-1;
    str=sc.nextLine();
    while(sc.hasNext())
    {
      if(str=="end")
      {
        break;
      }
      hang++;
      i = str.indexOf(x);
      if(i!=-1)
      {
        System.out.println(hang+" "+str);
        count++;
        if(count==n)
        {
          break;
        }
      }
      str=sc.nextLine();
    }
    System.out.println(count);
  }
}