本题链接: DHCP服务器
本博客给出本题截图:
C++
#include <iostream> #include <cstring> #include <algorithm> using namespace std; const int N = 10010; int n, m, t_def, t_max, t_min; string h; struct IP { int state; int t; string owner; }ip[N]; void update_ips_state(int tc) { for (int i = 1; i <= n; i ++ ) if (ip[i].t && ip[i].t <= tc) { if (ip[i].state == 1) { ip[i].state = 0; ip[i].owner = ""; ip[i].t = 0; } else { ip[i].state = 3; ip[i].t = 0; } } } int get_ip_by_owner(string client) { for (int i = 1; i <= n; i ++ ) if (ip[i].owner == client) return i; return 0; } int get_ip_by_state(int state) { for (int i = 1; i <= n; i ++ ) if (ip[i].state == state) return i; return 0; } int main() { cin >> n >> t_def >> t_max >> t_min >> h; cin >> m; while (m -- ) { int tc; string client, server, type; int id, te; cin >> tc >> client >> server >> type >> id >> te; if (server != h && server != "*") { if (type != "REQ") continue; } if (type != "DIS" && type != "REQ") continue; if (server == "*" && type != "DIS" || server == h && type == "DIS") continue; update_ips_state(tc); if (type == "DIS") { int k = get_ip_by_owner(client); if (!k) k = get_ip_by_state(0); if (!k) k = get_ip_by_state(3); if (!k) continue; ip[k].state = 1, ip[k].owner = client; if (!te) ip[k].t = tc + t_def; else { int t = te - tc; t = max(t, t_min), t = min(t, t_max); ip[k].t = tc + t; } cout << h << ' ' << client << ' ' << "OFR" << ' ' << k << ' ' << ip[k].t << endl; } else { if (server != h) { for (int i = 1; i <= n; i ++ ) if (ip[i].owner == client && ip[i].state == 1) { ip[i].state = 0; ip[i].owner = ""; ip[i].t = 0; } continue; } if (!(id >= 1 && id <= n && ip[id].owner == client)) cout << h << ' ' << client << ' ' << "NAK" << ' ' << id << ' ' << 0 << endl; else { ip[id].state = 2; if (!te) ip[id].t = tc + t_def; else { int t = te - tc; t = max(t, t_min), t = min(t, t_max); ip[id].t = tc + t; } cout << h << ' ' << client << ' ' << "ACK" << ' ' << id << ' ' << ip[id].t << endl; } } } return 0; }
总结
大模拟题,近几年csp认证考试中比较简单的一道模拟题
阅读理解 + 细致
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