上篇我们介绍完了fail-fast 机制,下面我们将接着介绍List的另一个实现类LinkedList。
我们将从以下几个方面介绍
1.LinkedList的介绍
2.LinkedList的数据结构
3.LinkedList的源码分析(基于JDK1.8)
4.LinkedList的遍历方式
5.LinkedList的示例
6.ArrayList与LinkedList的区别
LinkedList的介绍
LinkedList的定义
public class LinkedList<E> extends AbstractSequentialList<E> implements List<E>, Deque<E>, Cloneable, java.io.Serializable{}
LinkedList是一个继承于AbstractSequentialList的双向链表,可以被当作堆栈,双向队列,队列进行操作。
LinkedList实现了List,可以被当作队列进行操作。
LinkedList 实现了Deque,可以被当作双向队列进行操作。
LinkedList实现了Cloneable,可以被克隆。
LinkedList实现了java.io.Serializable,可以被序列化
LinkedList是线程不安全的。
PS:
LinkedList的数据结构
LinkedList的API
LinkedList的API boolean add(E object) void add(int location, E object) boolean addAll(Collection<? extends E> collection) boolean addAll(int location, Collection<? extends E> collection) void addFirst(E object) void addLast(E object) void clear() Object clone() boolean contains(Object object) Iterator<E> descendingIterator() E element() E get(int location) E getFirst() E getLast() int indexOf(Object object) int lastIndexOf(Object object) ListIterator<E> listIterator(int location) boolean offer(E o) boolean offerFirst(E e) boolean offerLast(E e) E peek() E peekFirst() E peekLast() E poll() E pollFirst() E pollLast() E pop() void push(E e) E remove() E remove(int location) boolean remove(Object object) E removeFirst() boolean removeFirstOccurrence(Object o) E removeLast() boolean removeLastOccurrence(Object o) E set(int location, E object) int size() <T> T[] toArray(T[] contents) Object[] toArray()
LinkedList的类图如下
LinkedList 本质上是一个双向链表。
LinkedList 包含两个重要的成员 header和size。
header是双向链表的表头,是双向链表节点所对应的类Entry的实例。Entry中包含成员变量: previous, next, element。其中,previous是该节点的上一个节点,next是该节点的下一个节点,element是该节点所包含的值。
size是双向链表中节点的个数。
LinkedList源码解析(基于jdk 1.8)
为了更好的了解LinkedList的原理,下面我们对LinkedList的源码进行分析下。
在阅读源码之前,我们先对LinkedList的整体实现进行大致说明:
LinkedList 实际上是通过双向链表去实现的。既然是双向链表,那么它的顺序访问会非常高效,随机访问效率比较低。
既然LinkedList是通过双向链表的,但是它也实现了List 接口(也就是说它实现了get(int index)和remove(int index) 等通过索引值来获取,移除节点的函数)。
LinkedList 是如何实现List的这些接口的,如何将双向链表和索引值联系起来的?
实际原理是,它是通过一个计数索引值来实现的,例如,当我们调用get(int index)时,首先index与双向链表长度的1/2 进行比较。如果前者大,则从链表头开始往后查找,直到找到location位置;否则,从链表末尾开始先前查找,直到找到location位置。
这就是双向链表好索引值联系起来的方法。
接下来开始阅读源码
public class LinkedList<E>
extends AbstractSequentialList<E>
implements List<E>, Deque<E>, Cloneable, java.io.Serializable
{
transient int size = 0;
/**
* Pointer to first node.(定义第一个节点)
* Invariant: (first == null && last == null) ||
* (first.prev == null && first.item != null)
*/
transient Node<E> first;
/**
* Pointer to last node.(定义最后一个节点)
* Invariant: (first == null && last == null) ||
* (last.next == null && last.item != null)
*/
transient Node<E> last;
/**
* Constructs an empty list.(初始化一个空的list)
*/
public LinkedList() {
}
/**
* Constructs a list containing the elements of the specified
* collection, in the order they are returned by the collection's
* iterator.
* 包含“集合”的构造函数,创建一个包含"集合"的LinkedList
* @param c the collection whose elements are to be placed into this list
* @throws NullPointerException if the specified collection is null
*/
public LinkedList(Collection<? extends E> c) {
this();
addAll(c);
}
/**
* 获取第一个元素
* Links e as first element.
*/
private void linkFirst(E e) {
final Node<E> f = first;
final Node<E> newNode = new Node<>(null, e, f);
first = newNode;
if (f == null)
last = newNode;
else
f.prev = newNode;
size++;
modCount++;
}
/**
* 获取最后一个元素
* Links e as last element.
*/
void linkLast(E e) {
final Node<E> l = last;
final Node<E> newNode = new Node<>(l, e, null);
last = newNode;
if (l == null)
first = newNode;
else
l.next = newNode;
size++;
modCount++;
}
/**
* Inserts element e before non-null Node succ.
* 在节点succ之前增加元素
*/
void linkBefore(E e, Node<E> succ) {
// assert succ != null;
final Node<E> pred = succ.prev;
final Node<E> newNode = new Node<>(pred, e, succ);
succ.prev = newNode;
if (pred == null)
first = newNode;
else
pred.next = newNode;
size++;
modCount++;
}
/**
* Unlinks non-null first node f.
*
*/
private E unlinkFirst(Node<E> f) {
// assert f == first && f != null;
final E element = f.item;
final Node<E> next = f.next;
f.item = null;
f.next = null; // help GC
first = next;
if (next == null)
last = null;
else
next.prev = null;
size--;
modCount++;
return element;
}
/**
* Unlinks non-null last node l.
*/
private E unlinkLast(Node<E> l) {
// assert l == last && l != null;
final E element = l.item;
final Node<E> prev = l.prev;
l.item = null;
l.prev = null; // help GC
last = prev;
if (prev == null)
first = null;
else
prev.next = null;
size--;
modCount++;
return element;
}
/**
* Unlinks non-null node x.
*/
E unlink(Node<E> x) {
// assert x != null;
final E element = x.item;
final Node<E> next = x.next;
final Node<E> prev = x.prev;
if (prev == null) {
first = next;
} else {
prev.next = next;
x.prev = null;
}
if (next == null) {
last = prev;
} else {
next.prev = prev;
x.next = null;
}
x.item = null;
size--;
modCount++;
return element;
}
/**
* Returns the first element in this list.
* 返回该集合的第一个元素
* @return the first element in this list
* @throws NoSuchElementException if this list is empty
*/
public E getFirst() {
final Node<E> f = first;
if (f == null)
throw new NoSuchElementException();
return f.item;
}
/**
* Returns the last element in this list.
* 返回该集合的最后一个元素
* @return the last element in this list
* @throws NoSuchElementException if this list is empty
*/
public E getLast() {
final Node<E> l = last;
if (l == null)
throw new NoSuchElementException();
return l.item;
}
/**
* Removes and returns the first element from this list.
* 从集合中移除掉第一个元素
* @return the first element from this list
* @throws NoSuchElementException if this list is empty
*/
public E removeFirst() {
final Node<E> f = first;
if (f == null)
throw new NoSuchElementException();
return unlinkFirst(f);
}
/**
* Removes and returns the last element from this list.
* 从集合中移除掉最后一个元素
* @return the last element from this list
* @throws NoSuchElementException if this list is empty
*/
public E removeLast() {
final Node<E> l = last;
if (l == null)
throw new NoSuchElementException();
return unlinkLast(l);
}
/**
* Inserts the specified element at the beginning of this list.
* 从该集合中插入一个元素,插入为第一个
* @param e the element to add
*/
public void addFirst(E e) {
linkFirst(e);
}
/**
* Appends the specified element to the end of this list.
* 从该集合中插入一个元素,插入为最后一个
* <p>This method is equivalent to {@link #add}.
*
* @param e the element to add
*/
public void addLast(E e) {
linkLast(e);
}
/**
* Returns {@code true} if this list contains the specified element.
* 查找集合中是否某元素
*/
public boolean contains(Object o) {
return indexOf(o) != -1;
}
/**
* Returns the number of elements in this list.
* 返回集合的大小
* @return the number of elements in this list
*/
public int size() {
return size;
}
/**
* Appends the specified element to the end of this list.
* 将元素添加到集合尾部
*/
public boolean add(E e) {
linkLast(e);
return true;
}
/**
* Removes the first occurrence of the specified element from this list,
* if it is present. If this list does not contain the element, it is
* unchanged. More formally, removes the element with the lowest index
* {@code i} such that
* 从集合中移除某个元素
*/
public boolean remove(Object o) {
if (o == null) {
for (Node<E> x = first; x != null; x = x.next) {
if (x.item == null) {
unlink(x);
return true;
}
}
} else {
for (Node<E> x = first; x != null; x = x.next) {
if (o.equals(x.item)) {
unlink(x);
return true;
}
}
}
return false;
}
/**
* Appends all of the elements in the specified collection to the end of
* this list, in the order that they are returned by the specified
* collection's iterator. The behavior of this operation is undefined if
* the specified collection is modified while the operation is in
* progress. (Note that this will occur if the specified collection is
* this list, and it's nonempty.)
* 将Collection c 添加到该集合中,添加到集合尾部
*/
public boolean addAll(Collection<? extends E> c) {
return addAll(size, c);
}
/**
* Inserts all of the elements in the specified collection into this
* list, starting at the specified position. Shifts the element
* currently at that position (if any) and any subsequent elements to
* the right (increases their indices). The new elements will appear
* in the list in the order that they are returned by the
* specified collection's iterator.
* 将Collection c 添加到该集合中,添加到集合指定位置
*/
public boolean addAll(int index, Collection<? extends E> c) {
checkPositionIndex(index);
Object[] a = c.toArray();
int numNew = a.length;
if (numNew == 0)
return false;
Node<E> pred, succ;
if (index == size) {
succ = null;
pred = last;
} else {
succ = node(index);
pred = succ.prev;
}
for (Object o : a) {
@SuppressWarnings("unchecked") E e = (E) o;
Node<E> newNode = new Node<>(pred, e, null);
if (pred == null)
first = newNode;
else
pred.next = newNode;
pred = newNode;
}
if (succ == null) {
last = pred;
} else {
pred.next = succ;
succ.prev = pred;
}
size += numNew;
modCount++;
return true;
}
/**
* Removes all of the elements from this list.
* The list will be empty after this call returns.
* 从集合中移除掉所有元素
*/
public void clear() {
for (Node<E> x = first; x != null; ) {
Node<E> next = x.next;
x.item = null;
x.next = null;
x.prev = null;
x = next;
}
first = last = null;
size = 0;
modCount++;
}
// Positional Access Operations
/**
* Returns the element at the specified position in this list.
* 返回元素在集合中的位置
* @param index index of the element to return
* @return the element at the specified position in this list
* @throws IndexOutOfBoundsException {@inheritDoc}
*/
public E get(int index) {
checkElementIndex(index);
return node(index).item;
}
/**
* Replaces the element at the specified position in this list with the
* specified element.
* 替换指定位置的元素的值
*/
public E set(int index, E element) {
checkElementIndex(index);
Node<E> x = node(index);
E oldVal = x.item;
x.item = element;
return oldVal;
}
/**
* Inserts the specified element at the specified position in this list.
* Shifts the element currently at that position (if any) and any
* subsequent elements to the right (adds one to their indices).
* 将元素添加到集合中的指定位置
*/
public void add(int index, E element) {
checkPositionIndex(index);
if (index == size)
linkLast(element);
else linkBefore(element, node(index)); } /** * Removes the element at the specified position in this list. Shifts any * subsequent elements to the left (subtracts one from their indices). * Returns the element that was removed from the list. * 移除指定位置的元素 */ public E remove(int index) { checkElementIndex(index); return unlink(node(index)); } /** * Tells if the argument is the index of an existing element. */ private boolean isElementIndex(int index) { return index >= 0 && index < size; } /** * Tells if the argument is the index of a valid position for an * iterator or an add operation. */ private boolean isPositionIndex(int index) { return index >= 0 && index <= size; } /** * Constructs an IndexOutOfBoundsException detail message. * Of the many possible refactorings of the error handling code, * this "outlining" performs best with both server and client VMs. */ private String outOfBoundsMsg(int index) { return "Index: "+index+", Size: "+size; } private void checkElementIndex(int index) { if (!isElementIndex(index)) throw new IndexOutOfBoundsException(outOfBoundsMsg(index)); } private void checkPositionIndex(int index) { if (!isPositionIndex(index)) throw new IndexOutOfBoundsException(outOfBoundsMsg(index)); } /** * Returns the (non-null) Node at the specified element index. * */ Node<E> node(int index) { // assert isElementIndex(index); if (index < (size >> 1)) { Node<E> x = first; for (int i = 0; i < index; i++) x = x.next; return x; } else { Node<E> x = last; for (int i = size - 1; i > index; i--) x = x.prev; return x; } } // Search Operations /** * Returns the index of the first occurrence of the specified element * in this list, or -1 if this list does not contain the element. * More formally, returns the lowest index {@code i} such that * <tt>(o==null ? get(i)==null : o.equals(get(i)))</tt>, * or -1 if there is no such index. * * @param o element to search for * @return the index of the first occurrence of the specified element in * this list, or -1 if this list does not contain the element */ public int indexOf(Object o) { int index = 0; if (o == null) { for (Node<E> x = first; x != null; x = x.next) { if (x.item == null) return index; index++; } } else { for (Node<E> x = first; x != null; x = x.next) { if (o.equals(x.item)) return index; index++; } } return -1; } /** * Returns the index of the last occurrence of the specified element * in this list, or -1 if this list does not contain the element. * More formally, returns the highest index {@code i} such that * <tt>(o==null ? get(i)==null : o.equals(get(i)))</tt>, * or -1 if there is no such index. * * @param o element to search for * @return the index of the last occurrence of the specified element in * this list, or -1 if this list does not contain the element */ public int lastIndexOf(Object o) { int index = size; if (o == null) { for (Node<E> x = last; x != null; x = x.prev) { index--; if (x.item == null) return index; } } else { for (Node<E> x = last; x != null; x = x.prev) { index--; if (o.equals(x.item)) return index; } } return -1; } // Queue operations. /** * Retrieves, but does not remove, the head (first element) of this list. * * @return the head of this list, or {@code null} if this list is empty * @since 1.5 */ public E peek() { final Node<E> f = first; return (f == null) ? null : f.item; } /** * Retrieves, but does not remove, the head (first element) of this list. * * @return the head of this list * @throws NoSuchElementException if this list is empty * @since 1.5 */ public E element() { return getFirst(); } /** * Retrieves and removes the head (first element) of this list. * * @return the head of this list, or {@code null} if this list is empty * @since 1.5 */ public E poll() { final Node<E> f = first; return (f == null) ? null : unlinkFirst(f); } /** * Retrieves and removes the head (first element) of this list. * * @return the head of this list * @throws NoSuchElementException if this list is empty * @since 1.5 */ public E remove() { return removeFirst(); } /** * Adds the specified element as the tail (last element) of this list. * * @param e the element to add * @return {@code true} (as specified by {@link Queue#offer}) * @since 1.5 */ public boolean offer(E e) { return add(e); } // Deque operations /** * Inserts the specified element at the front of this list. * * @param e the element to insert * @return {@code true} (as specified by {@link Deque#offerFirst}) * @since 1.6 */ public boolean offerFirst(E e) { addFirst(e); return true; } /** * Inserts the specified element at the end of this list. * * @param e the element to insert * @return {@code true} (as specified by {@link Deque#offerLast}) * @since 1.6 */ public boolean offerLast(E e) { addLast(e); return true; } /** * Retrieves, but does not remove, the first element of this list, * or returns {@code null} if this list is empty. * * @return the first element of this list, or {@code null} * if this list is empty * @since 1.6 */ public E peekFirst() { final Node<E> f = first; return (f == null) ? null : f.item; } /** * Retrieves, but does not remove, the last element of this list, * or returns {@code null} if this list is empty. * * @return the last element of this list, or {@code null} * if this list is empty * @since 1.6 */ public E peekLast() { final Node<E> l = last; return (l == null) ? null : l.item; } /** * Retrieves and removes the first element of this list, * or returns {@code null} if this list is empty. * * @return the first element of this list, or {@code null} if * this list is empty * @since 1.6 */ public E pollFirst() { final Node<E> f = first; return (f == null) ? null : unlinkFirst(f); } /** * Retrieves and removes the last element of this list, * or returns {@code null} if this list is empty. * * @return the last element of this list, or {@code null} if * this list is empty * @since 1.6 */ public E pollLast() { final Node<E> l = last; return (l == null) ? null : unlinkLast(l); } /** * Pushes an element onto the stack represented by this list. In other * words, inserts the element at the front of this list. * * <p>This method is equivalent to {@link #addFirst}. * * @param e the element to push * @since 1.6 */ public void push(E e) { addFirst(e); } /** * Pops an element from the stack represented by this list. In other * words, removes and returns the first element of this list. * * <p>This method is equivalent to {@link #removeFirst()}. * * @return the element at the front of this list (which is the top * of the stack represented by this list) * @throws NoSuchElementException if this list is empty * @since 1.6 */ public E pop() { return removeFirst(); } /** * Removes the first occurrence of the specified element in this * list (when traversing the list from head to tail). If the list * does not contain the element, it is unchanged. * * @param o element to be removed from this list, if present * @return {@code true} if the list contained the specified element * @since 1.6 */ public boolean removeFirstOccurrence(Object o) { return remove(o); } /** * Removes the last occurrence of the specified element in this * list (when traversing the list from head to tail). If the list * does not contain the element, it is unchanged. * * @param o element to be removed from this list, if present * @return {@code true} if the list contained the specified element * @since 1.6 */ public boolean removeLastOccurrence(Object o) { if (o == null) { for (Node<E> x = last; x != null; x = x.prev) { if (x.item == null) { unlink(x); return true; } } } else { for (Node<E> x = last; x != null; x = x.prev) { if (o.equals(x.item)) { unlink(x); return true; } } } return false; } /** * Returns a list-iterator of the elements in this list (in proper * sequence), starting at the specified position in the list. * Obeys the general contract of {@code List.listIterator(int)}.<p> * * The list-iterator is <i>fail-fast</i>: if the list is structurally * modified at any time after the Iterator is created, in any way except * through the list-iterator's own {@code remove} or {@code add} * methods, the list-iterator will throw a * {@code ConcurrentModificationException}. Thus, in the face of * concurrent modification, the iterator fails quickly and cleanly, rather * than risking arbitrary, non-deterministic behavior at an undetermined * time in the future. * * @param index index of the first element to be returned from the * list-iterator (by a call to {@code next}) * @return a ListIterator of the elements in this list (in proper * sequence), starting at the specified position in the list * @throws IndexOutOfBoundsException {@inheritDoc} * @see List#listIterator(int) */ public ListIterator<E> listIterator(int index) { checkPositionIndex(index); return new ListItr(index); } private class ListItr implements ListIterator<E> { private Node<E> lastReturned; private Node<E> next; private int nextIndex; private int expectedModCount = modCount; ListItr(int index) { // assert isPositionIndex(index); next = (index == size) ? null : node(index); nextIndex = index; } public boolean hasNext() { return nextIndex < size; } public E next() { checkForComodification(); if (!hasNext()) throw new NoSuchElementException(); lastReturned = next; next = next.next; nextIndex++; return lastReturned.item; } public boolean hasPrevious() { return nextIndex > 0; } public E previous() { checkForComodification(); if (!hasPrevious()) throw new NoSuchElementException(); lastReturned = next = (next == null) ? last : next.prev; nextIndex--; return lastReturned.item; } public int nextIndex() { return nextIndex; } public int previousIndex() { return nextIndex - 1; } public void remove() { checkForComodification(); if (lastReturned == null) throw new IllegalStateException(); Node<E> lastNext = lastReturned.next; unlink(lastReturned); if (next == lastReturned) next = lastNext; else nextIndex--; lastReturned = null; expectedModCount++; } public void set(E e) { if (lastReturned == null) throw new IllegalStateException(); checkForComodification(); lastReturned.item = e; } public void add(E e) { checkForComodification(); lastReturned = null; if (next == null) linkLast(e); else linkBefore(e, next); nextIndex++; expectedModCount++; } public void forEachRemaining(Consumer<? super E> action) { Objects.requireNonNull(action); while (modCount == expectedModCount && nextIndex < size) { action.accept(next.item); lastReturned = next; next = next.next; nextIndex++; } checkForComodification(); } final void checkForComodification() { if (modCount != expectedModCount) throw new ConcurrentModificationException(); } } // 双向链表的节点所对应的数据结构。 // 包含3部分:上一节点,下一节点,当前节点值。 private static class Node<E> { // 当前节点所对应的值 E item; // 下一节点 Node<E> next; //上一节点 Node<E> prev; /** * 链表节点的构造函数 */ Node(Node<E> prev, E element, Node<E> next) { this.item = element; this.next = next; this.prev = prev; } } /** * @since 1.6 */ public Iterator<E> descendingIterator() { return new DescendingIterator(); } /** * Adapter to provide descending iterators via ListItr.previous * 反向迭代器 */ private class DescendingIterator implements Iterator<E> { private final ListItr itr = new ListItr(size()); public boolean hasNext() { return itr.hasPrevious(); } public E next() { return itr.previous(); } public void remove() { itr.remove(); } } @SuppressWarnings("unchecked") private LinkedList<E> superClone() { try { return (LinkedList<E>) super.clone(); } catch (CloneNotSupportedException e) { throw new InternalError(e); } } /** * Returns a shallow copy of this {@code LinkedList}. (The elements * themselves are not cloned.) * 克隆函数,返回LinkedList的克隆对象 */ public Object clone() { LinkedList<E> clone = superClone(); // Put clone into "virgin" state clone.first = clone.last = null; clone.size = 0; clone.modCount = 0; // Initialize clone with our elements for (Node<E> x = first; x != null; x = x.next) clone.add(x.item); return clone; } /** * Returns an array containing all of the elements in this list * in proper sequence (from first to last element). * 返回LinkedList的数组Object[] */ public Object[] toArray() { Object[] result = new Object[size]; int i = 0; for (Node<E> x = first; x != null; x = x.next) result[i++] = x.item; return result; } /** * 返回LinkedList的模板数组。所谓模板数组,即可以将T设为任意的数据类型 */ @SuppressWarnings("unchecked") public <T> T[] toArray(T[] a) { // 若数组a的大小<LinkedList的元素个数,(意味着数组a不足以容纳LinkedList中的全部元素) if (a.length < size) a = (T[])java.lang.reflect.Array.newInstance( a.getClass().getComponentType(), size); int i = 0; Object[] result = a; for (Node<E> x = first; x != null; x = x.next) result[i++] = x.item; if (a.length > size) a[size] = null; return a; } private static final long serialVersionUID = 876323262645176354L; /** * Saves the state of this {@code LinkedList} instance to a stream * (that is, serializes it). *// java.io.Serializable的写入函数 * 将LinkedList的“容量,所有的元素值”都写入到输出流中 */ private void writeObject(java.io.ObjectOutputStream s) throws java.io.IOException { // Write out any hidden serialization magic s.defaultWriteObject(); // Write out size s.writeInt(size); // Write out all elements in the proper order. for (Node<E> x = first; x != null; x = x.next) s.writeObject(x.item); } /** * Reconstitutes this {@code LinkedList} instance from a stream * (that is, deserializes it). */ @SuppressWarnings("unchecked") private void readObject(java.io.ObjectInputStream s) throws java.io.IOException, ClassNotFoundException { // Read in any hidden serialization magic s.defaultReadObject(); // Read in size int size = s.readInt(); // Read in all elements in the proper order. for (int i = 0; i < size; i++) linkLast((E)s.readObject()); } } } /** * Retrieves, but does not remove, the head (first element) of this list. * * @return the head of this list * @throws NoSuchElementException if this list is empty * @since 1.5 */ public E element() { return getFirst(); } /** * Retrieves and removes the head (first element) of this list. * * @return the head of this list, or {@code null} if this list is empty * @since 1.5 */ public E poll() { final Node<E> f = first; return (f == null) ? null : unlinkFirst(f); } /** * Retrieves and removes the head (first element) of this list. * * @return the head of this list * @throws NoSuchElementException if this list is empty * @since 1.5 */ public E remove() { return removeFirst(); } /** * Adds the specified element as the tail (last element) of this list. * * @param e the element to add * @return {@code true} (as specified by {@link Queue#offer}) * @since 1.5 */ public boolean offer(E e) { return add(e); } // Deque operations /** * Inserts the specified element at the front of this list. * * @param e the element to insert * @return {@code true} (as specified by {@link Deque#offerFirst}) * @since 1.6 */ public boolean offerFirst(E e) { addFirst(e); return true; } /** * Inserts the specified element at the end of this list. * * @param e the element to insert * @return {@code true} (as specified by {@link Deque#offerLast}) * @since 1.6 */ public boolean offerLast(E e) { addLast(e); return true; } /** * Retrieves, but does not remove, the first element of this list, * or returns {@code null} if this list is empty. * * @return the first element of this list, or {@code null} * if this list is empty * @since 1.6 */ public E peekFirst() { final Node<E> f = first; return (f == null) ? null : f.item; } /** * Retrieves, but does not remove, the last element of this list, * or returns {@code null} if this list is empty. * * @return the last element of this list, or {@code null} * if this list is empty * @since 1.6 */ public E peekLast() { final Node<E> l = last; return (l == null) ? null : l.item; } /** * Retrieves and removes the first element of this list, * or returns {@code null} if this list is empty. * * @return the first element of this list, or {@code null} if * this list is empty * @since 1.6 */ public E pollFirst() { final Node<E> f = first; return (f == null) ? null : unlinkFirst(f); } /** * Retrieves and removes the last element of this list, * or returns {@code null} if this list is empty. * * @return the last element of this list, or {@code null} if * this list is empty * @since 1.6 */ public E pollLast() { final Node<E> l = last; return (l == null) ? null : unlinkLast(l); } /** * Pushes an element onto the stack represented by this list. In other * words, inserts the element at the front of this list. * * <p>This method is equivalent to {@link #addFirst}. * * @param e the element to push * @since 1.6 */ public void push(E e) { addFirst(e); } /** * Pops an element from the stack represented by this list. In other * words, removes and returns the first element of this list. * * <p>This method is equivalent to {@link #removeFirst()}. * * @return the element at the front of this list (which is the top * of the stack represented by this list) * @throws NoSuchElementException if this list is empty * @since 1.6 */ public E pop() { return removeFirst(); } /** * Removes the first occurrence of the specified element in this * list (when traversing the list from head to tail). If the list * does not contain the element, it is unchanged. * * @param o element to be removed from this list, if present * @return {@code true} if the list contained the specified element * @since 1.6 */ public boolean removeFirstOccurrence(Object o) { return remove(o); } /** * Removes the last occurrence of the specified element in this * list (when traversing the list from head to tail). If the list * does not contain the element, it is unchanged. * * @param o element to be removed from this list, if present * @return {@code true} if the list contained the specified element * @since 1.6 */ public boolean removeLastOccurrence(Object o) { if (o == null) { for (Node<E> x = last; x != null; x = x.prev) { if (x.item == null) { unlink(x); return true; } } } else { for (Node<E> x = last; x != null; x = x.prev) { if (o.equals(x.item)) { unlink(x); return true; } } } return false; } /** * Returns a list-iterator of the elements in this list (in proper * sequence), starting at the specified position in the list. * Obeys the general contract of {@code List.listIterator(int)}.<p> * * The list-iterator is <i>fail-fast</i>: if the list is structurally * modified at any time after the Iterator is created, in any way except * through the list-iterator's own {@code remove} or {@code add} * methods, the list-iterator will throw a * {@code ConcurrentModificationException}. Thus, in the face of * concurrent modification, the iterator fails quickly and cleanly, rather * than risking arbitrary, non-deterministic behavior at an undetermined * time in the future. * * @param index index of the first element to be returned from the * list-iterator (by a call to {@code next}) * @return a ListIterator of the elements in this list (in proper * sequence), starting at the specified position in the list * @throws IndexOutOfBoundsException {@inheritDoc} * @see List#listIterator(int) */ public ListIterator<E> listIterator(int index) { checkPositionIndex(index); return new ListItr(index); } private class ListItr implements ListIterator<E> { private Node<E> lastReturned; private Node<E> next; private int nextIndex; private int expectedModCount = modCount; ListItr(int index) { // assert isPositionIndex(index); next = (index == size) ? null : node(index); nextIndex = index; } public boolean hasNext() { return nextIndex < size; } public E next() { checkForComodification(); if (!hasNext()) throw new NoSuchElementException(); lastReturned = next; next = next.next; nextIndex++; return lastReturned.item; } public boolean hasPrevious() { return nextIndex > 0; } public E previous() { checkForComodification(); if (!hasPrevious()) throw new NoSuchElementException(); lastReturned = next = (next == null) ? last : next.prev; nextIndex--; return lastReturned.item; } public int nextIndex() { return nextIndex; } public int previousIndex() { return nextIndex - 1; } public void remove() { checkForComodification(); if (lastReturned == null) throw new IllegalStateException(); Node<E> lastNext = lastReturned.next; unlink(lastReturned); if (next == lastReturned) next = lastNext; else nextIndex--; lastReturned = null; expectedModCount++; } public void set(E e) { if (lastReturned == null) throw new IllegalStateException(); checkForComodification(); lastReturned.item = e; } public void add(E e) { checkForComodification(); lastReturned = null; if (next == null) linkLast(e); else linkBefore(e, next); nextIndex++; expectedModCount++; } public void forEachRemaining(Consumer<? super E> action) { Objects.requireNonNull(action); while (modCount == expectedModCount && nextIndex < size) { action.accept(next.item); lastReturned = next; next = next.next; nextIndex++; } checkForComodification(); } final void checkForComodification() { if (modCount != expectedModCount) throw new ConcurrentModificationException(); } } // 双向链表的节点所对应的数据结构。 // 包含3部分:上一节点,下一节点,当前节点值。 private static class Node<E> { // 当前节点所对应的值 E item; // 下一节点 Node<E> next; //上一节点 Node<E> prev; /** * 链表节点的构造函数 */ Node(Node<E> prev, E element, Node<E> next) { this.item = element; this.next = next; this.prev = prev; } } /** * @since 1.6 */ public Iterator<E> descendingIterator() { return new DescendingIterator(); } /** * Adapter to provide descending iterators via ListItr.previous * 反向迭代器 */ private class DescendingIterator implements Iterator<E> { private final ListItr itr = new ListItr(size()); public boolean hasNext() { return itr.hasPrevious(); } public E next() { return itr.previous(); } public void remove() { itr.remove(); } } @SuppressWarnings("unchecked") private LinkedList<E> superClone() { try { return (LinkedList<E>) super.clone(); } catch (CloneNotSupportedException e) { throw new InternalError(e); } } /** * Returns a shallow copy of this {@code LinkedList}. (The elements * themselves are not cloned.) * 克隆函数,返回LinkedList的克隆对象 */ public Object clone() { LinkedList<E> clone = superClone(); // Put clone into "virgin" state clone.first = clone.last = null; clone.size = 0; clone.modCount = 0; // Initialize clone with our elements for (Node<E> x = first; x != null; x = x.next) clone.add(x.item); return clone; } /** * Returns an array containing all of the elements in this list * in proper sequence (from first to last element). * 返回LinkedList的数组Object[] */ public Object[] toArray() { Object[] result = new Object[size]; int i = 0; for (Node<E> x = first; x != null; x = x.next) result[i++] = x.item; return result; } /** * 返回LinkedList的模板数组。所谓模板数组,即可以将T设为任意的数据类型 */ @SuppressWarnings("unchecked") public <T> T[] toArray(T[] a) { // 若数组a的大小<LinkedList的元素个数,(意味着数组a不足以容纳LinkedList中的全部元素) if (a.length < size) a = (T[])java.lang.reflect.Array.newInstance( a.getClass().getComponentType(), size); int i = 0; Object[] result = a; for (Node<E> x = first; x != null; x = x.next) result[i++] = x.item; if (a.length > size) a[size] = null; return a; } private static final long serialVersionUID = 876323262645176354L; /** * Saves the state of this {@code LinkedList} instance to a stream * (that is, serializes it). *// java.io.Serializable的写入函数 * 将LinkedList的“容量,所有的元素值”都写入到输出流中 */ private void writeObject(java.io.ObjectOutputStream s) throws java.io.IOException { // Write out any hidden serialization magic s.defaultWriteObject(); // Write out size s.writeInt(size); // Write out all elements in the proper order. for (Node<E> x = first; x != null; x = x.next) s.writeObject(x.item); } /** * Reconstitutes this {@code LinkedList} instance from a stream * (that is, deserializes it). */ @SuppressWarnings("unchecked") private void readObject(java.io.ObjectInputStream s) throws java.io.IOException, ClassNotFoundException { // Read in any hidden serialization magic s.defaultReadObject(); // Read in size int size = s.readInt(); // Read in all elements in the proper order. for (int i = 0; i < size; i++) linkLast((E)s.readObject()); } }
总结:
LinkedList 实际上是通过双向链表来实现的。它包含一个非常重要内部类Node
Node是LinkedList对应的数据结构,该数据结构包含的属性有:当前节点对应的值,上一节点,下一节点。
从LinkedList的实现来看,其不存在容量不足的问题
LinkedList的克隆函数,即是将所有元素克隆到一个新的LinkedList对象中。
LinkedList实现java.io.Serializable,当写入输出流时,先写入容量,然后,写入每一个受保护的变量,读取输入流时,
先读取容量,然后,读取每一个元素。
由于LinkedList实现了Deque,而Deque接口提供了在双端队列两端访问元素的方法,提供了插入,移除和检查元素的方法。每种方法都存在两种形式,一种形式在操作失败时抛出异常,一种形式是返回特殊的值(null或者false)。
引用
http://blog.csdn.net/eson_15/article/details/51145788
http://www.cnblogs.com/skywang12345/p/3308807.html