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Re关于测评 这几天一直没有查看论坛，我找到问题了，是没能满足商户时间窗带来的惩罚。

Re我的结果校验代码全11条规则python 第九条规则有点问题， 我做了点小修改。 def verify9(arrange, ds_order_df, o2o_order_df):     # use the example to verify cal functions     #mix_path = ['A083','A083','A083','A083','A083','B5800','B7555','B7182','B8307','B8461','A083','A083','A083','B6528','S245','B3266','B3266','B2337','A083','A083','A083','A083','S294','B1940','B6104','B8926','B9072','B6103']     #orders = ['F6344','F6360','F6358','F6353','F6354','F6344','F6354','F6353','F6358','F6360','F6349','F6325','F6314','F6349','E0895','E0895','F6325','F6314','F6366','F6345','F6346','F6308','E1088','F6308','F6346','E1088','F6366','F6345']       mix_path = arrange.Addr.tolist()     orders = arrange.Order_id.tolist()     mix_arrange_df = pd.DataFrame({ 'Addr': mix_path, 'Order_id': orders})     mix_arrange_df['Courier_id'] = arrange.iloc[0].Courier_id     mix_arrange_df['Arrival_time'] = arrange.iloc[0].Arrival_time     mix_arrange_df['Departure'] = arrange.iloc[0].Departure     mix_arrange_df['Amount'] = 0     pre_e = mix_arrange_df.iloc[0]     pre_addr = pre_e.Addr     pre_order = pre_e.Order_id     pre_departure = arrange.iloc[0].Departure     if 'F' in pre_order:         amount = ds_order_df[ds_order_df['Order_id']==pre_order].Num.values[0]     elif 'E' in pre_order:         amount = o2o_order_df[o2o_order_df['Order_id']==pre_order].Num.values[0]     new_mix_arrange_df = pd.DataFrame({'Courier_id': [arrange.iloc[0].Courier_id], 'Addr': [pre_addr], 'Arrival_time': [arrange.iloc[0].Arrival_time], 'Departure': [arrange.iloc[0].Departure], 'Amount': [amount],  'Order_id': [pre_order]})     for i in range(1, len(mix_arrange_df)):         cur_e = mix_arrange_df.iloc         cur_addr = cur_e.Addr        cur_order = cur_e.Order_id        if 'A' in cur_addr:            arrival_time = pre_departure + cal_cost(pre_addr, cur_addr)            amount = ds_order_df[ds_order_df['Order_id']==cur_order].Num.values[0]            departure = arrival_time        elif 'B' in cur_addr and 'F' in cur_order:            arrival_time = pre_departure + cal_cost(pre_addr, cur_addr)            amount = -ds_order_df[ds_order_df['Order_id']==cur_order].Num.values[0]            departure = arrival_time + cal_proctime(abs(amount))        elif 'B' in cur_addr and 'E' in cur_order:            arrival_time = pre_departure + cal_cost(pre_addr, cur_addr)            amount = -o2o_order_df[o2o_order_df['Order_id']==cur_order].Num.values[0]            departure = arrival_time + cal_proctime(abs(amount))        elif 'S' in cur_addr:            arrival_time = pre_departure + cal_cost(pre_addr, cur_addr)            amount = o2o_order_df[o2o_order_df['Order_id']==cur_order].Num.values[0]            departure = max(time2min(o2o_order_df[o2o_order_df['Order_id']==cur_order].Pickup_time.values[0]), arrival_time)        new_mix_arrange_df = new_mix_arrange_df.append(pd.DataFrame({'Courier_id': [arrange.iloc[0].Courier_id], 'Addr': [cur_addr], 'Arrival_time': [arrival_time], 'Departure': [departure], 'Amount': [amount],  'Order_id': [cur_order]}))        cmp_e = arrange.iloc        if cur_addr != cmp_e.Addr or amount != cmp_e.Amount or arrival_time != cmp_e.Arrival_time or departure != cmp_e.Departure:            return False        pre_addr = cur_addr        pre_departure = departure    return True

Re我的提交结果验证程序 惩罚时间没有考虑，如果我把每个快递员最后派送时间加上成绩比较好，但是提交结果显示成绩很不理想，不知道是不是大量惩罚时间的原因，可是我没有发现o2o订单超出时间窗的情况。

Re提交结果规范 1487992370

Re官方样例离开时间问题 官方样例在哪？给个链接，谢谢。