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PolarDB的order by + limit 不走列存储查询，怎么解决？ SELECT t1.sell_record_id id,t1.sell_record_id,t1.sell_record_code,t1.deal_code_list,t1.sale_channel_code,t1.store_code,t1.shop_code,t1.express_code,t1.delivery_time,t1.plan_send_time,t1.record_time,t1.pay_time,t1.buyer_name,t1.express_no,t1.express_money,t1.payable_money,t1.paid_money,t1.fx_express_money,t1.fx_payable_money,t1.goods_weigh,t1.goods_num,t1.pay_type,t1.is_back,t1.pay_status,t1.order_status,t1.shipping_status,t1.must_occupy_inv,t1.lock_inv_status,t1.is_pending,t1.is_problem,t1.is_combine_new,t1.is_split_new,t1.is_change_record,t1.is_handwork,t1.is_copy,t1.sale_mode,t1.is_fenxiao,t1.is_rush,t1.is_replenish,t1.order_remark,t1.store_remark,t1.buyer_remark,t1.seller_remark,t1.seller_flag,t1.order_type,t1.is_hx,t1.cn_date,t1.return_status,t1.receiver_name,t1.receiver_phone,t1.receiver_mobile,t1.receiver_address,t1.is_bj,t1.bj_je,t1.invoice_status,main.transport_mode,main.virtual_store_code FROM oms_sell_record t1 LEFT JOIN oms_sell_record_main main ON t1.sell_record_code=main.record_code WHERE t1.shop_code IN('tb002','12697403','13961149','14632902','10688625','10805738','10688722','11665749','13706526','14034891','10783567','14765793','12597064','14398503','13552442','13074907','12854030','12697486','12707476','13552464','13236068','13400475','14594666','14590426','14993880','14994782','15016784','jd034','ht036','ht037','15035749','15070232') AND (t1.store_code IN ('WXCK001','WXCK002','WXCK003','WXCK004','WXCK005','WXCK006','WXCK007','WXCK008','SZCK001','JSJCK001','JSJCK002','JSJCK003','JSJCK004','JSJCK005','JSJCK006','JSJCK007','WXCK001-70','SZCK001-20','CGTEST') OR t1.store_code='' OR t1.store_code is NULL) AND t1.is_problem = 1 AND t1.order_status = 0 ORDER BY t1.record_time DESC LIMIT 0,1000
写回答
order by上有innodb索引，同时有limit，代价模型是根据经验公式计算查询代价的，这条sql算出来的代价是2600。show status like 'last_query_cost_for_imci';
行存实际执行时间是4s，cost算的偏低。已经优化了，再试试吧。此回答整理自钉群“PolarDB专家面对面 - HTAP（列存索引） ”
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