DEPARTMENTS表结构如下:
DEPARTMENT_ID(primary key),
DEPARTMENT_NAME,
LOCATION
EMPLOYEES表结构如下:
EMPLOYEE_ID(primary key),
EMPLOYEE_NAME,
EMPLOYEE_JOB,
MANAGER,
SALARY,
DEPARTMENT_ID
根据部门号由高而低,工资有低而高列出每个员工的姓名,部门号,工资select DEPARTMENT_ID as 部门号,EMPLOYEE_NAME as 姓名,SALARY as 工资 from EMPLOYEES order by DEPARTMENT_ID desc,SALARY asc
求另一种解决方法
这样的话SQL有两种写法:
法一
SELECT e.EMPLOYEE_NAME AS `姓名`,
d.DEPARTMENT_NAME AS `部门号`,
e.SALARY AS `工资`
FROM DEPARTMENTS AS d, EMPLOYEES AS e
WHERE e.DEPARTMENT_ID = d.DEPARTMENT_ID
ORDER BY d.DEPARTMENT_ID DESC, SALARY ASC
法二
SELECT e.EMPLOYEE_NAME AS `姓名`,
d.DEPARTMENT_NAME AS `部门号`,
e.SALARY AS `工资`
FROM EMPLOYEES AS e
LEFT JOIN DEPARTMENTS AS d
ON e.DEPARTMENT_ID = d.DEPARTMENT_ID
ORDER BY d.DEPARTMENT_ID DESC, SALARY ASC
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