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MySQL-使用来自三个表的数据和列创建新表?mysql

我正在尝试创建一个新表,该表将包含三个现有表中的选定数据。

现有的三个表设置如下,我想要的结果在底部:

people id last_name first_name email 1 Smith Fred Fred@.. 2 Jones Tom Tom@.. 3 Doe Jane Jane@..

taxonomy id taxonomy
1 age 2 gender 3 height

details id person_id detail_id content 1 1 1 36 2 1 2 M 3 1 3 5'10" 4 2 1 29 5 2 2 M 6 2 3 6'3" 7 3 1 27 8 3 2 F 9 3 3 5'8"

New Table id last_name first_name email age 1 Smith Fred Fred@.. 36 2 Jones Tom Tom@.. 29 3 Doe Jane Jane@.. 27 在此先感谢您的帮助!

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保持可爱mmm 2020-05-17 16:48:52 406 0
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  • 您需要进行三向联接:

    CREATE TABLE new_table AS SELECT p.*, d.content AS age FROM people AS p JOIN details AS d ON d.person_id = p.id JOIN taxonomy AS t ON t.id = d.detail_id WHERE t.taxonomy = 'age' 演示

    或者,如果您已经创建了表,则可以执行以下操作:

    INSERT INTO new_table (id, last_name, first_name, email, age) SELECT p.id, p.last_name, p.first_name, p.email, d.content AS age FROM people AS p JOIN details AS d ON d.person_id = p.id JOIN taxonomy AS t ON t.id = d.detail_id WHERE t.taxonomy = 'age' 要获得多个属性,您必须分别为每个属性将详细信息和分类表联接在一起:

    CREATE TABLE new_table AS SELECT p.*, d1.content AS age, d2.content AS gender, d3.content AS height FROM people AS p JOIN details AS d1 ON d1.person_id = p.id JOIN taxonomy AS t1 ON t1.id = d1.detail_id JOIN details AS d2 ON d2.person_id = p.id JOIN taxonomy AS t2 ON t2.id = d2.detail_id JOIN details AS d3 ON d3.person_id = p.id JOIN taxonomy AS t3 ON t3.id = d3.detail_id WHERE t1.taxonomy = 'age' AND t2.taxonomy = 'gender' AND t3.taxonomy = 'height'来源:stack overflow

    2020-05-17 16:55:54
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