jq +更新json文件并根据ID号附加名称
我们要根据以下规则编辑json文件
我们需要生成名称car0X_hyb.com -在mazda 字符串下（而X是ID号）
我们需要在我们的Linux机器上更新json文件
范例- ID=1
然后json将为
{
"toyota": [
"car1.com"
],
"mazda": [
"car01_hyb.com"
],
"ford": [
"car01_eng.com"
]
}
ID=4 ，那么json将为
{
"toyota": [
"car1.com"
],
"mazda": [
"car01_hyb.com",
"car02_hyb.com",
"car03_hyb.com",
"car04_hyb.com"
],
"ford": [
"car01_eng.com"
]
}
ID=6 ，那么json将为
{
"toyota": [
"car1.com"
],
"mazda": [
"car01_hyb.com",
"car02_hyb.com",
"car03_hyb.com",
"car04_hyb.com",
"car05_hyb.com",
"car06_hyb.com"
],
"ford": [
"car01_eng.com"
]
}
ID=10 ，那么json将为
{
"toyota": [
"car1.com"
],
"mazda": [
"car01_hyb.com",
"car02_hyb.com",
"car03_hyb.com",
"car04_hyb.com",
"car05_hyb.com",
"car06_hyb.com",
"car07_hyb.com",
"car08_hyb.com",
"car09_hyb.com",
"car10_hyb.com"
],
"ford": [
"car01_eng.com"
]
}
展开
收起
1
条回答
写回答
写回答
-
您可以使用生成后续数字流range，使用它们填充模板字符串，并根据结果组成一个数组，例如：
$ jq -n --argjson ID 5 '.mazda = [ range($ID) | "car\("0\(.+1)"[-2:])_hyb.com" ]' { "mazda": [ "car01_hyb.com", "car02_hyb.com", "car03_hyb.com", "car04_hyb.com", "car05_hyb.com" ] } $ jq -n --argjson ID 10 '.mazda = [ range($ID) | "car\("0\(.+1)"[-2:])_hyb.com" ]' { "mazda": [ "car01_hyb.com", "car02_hyb.com", "car03_hyb.com", "car04_hyb.com", "car05_hyb.com", "car06_hyb.com", "car07_hyb.com", "car08_hyb.com", "car09_hyb.com", "car10_hyb.com" ] }根据in字符的最大长度调整前导0s和。-2ID
2020-01-16 17:42:49赞同 展开评论 打赏
版权声明：本文内容由阿里云实名注册用户自发贡献，版权归原作者所有，阿里云开发者社区不拥有其著作权，亦不承担相应法律责任。具体规则请查看《阿里云开发者社区用户服务协议》和《阿里云开发者社区知识产权保护指引》。如果您发现本社区中有涉嫌抄袭的内容，填写侵权投诉表单进行举报，一经查实，本社区将立刻删除涉嫌侵权内容。
相关问答
