1065. A+B and C (64bit) (20) 溢出

Given three integers A, B and C in [-2⁶³, 2⁶³], you are supposed to tell whether A+B > C.

Input Specification:

The first line of the input gives the positive number of test cases, T (<=10). Then T test cases follow, each consists of a single line containing three integers A, B and C, separated by single spaces.

Output Specification:

For each test case, output in one line "Case #X: true" if A+B>C, or "Case #X: false" otherwise, where X is the case number (starting from 1).

3
1 2 3
2 3 4
9223372036854775807 -9223372036854775808 0

Case #1: false
Case #2: true
Case #3: false

#include <iostream>
using namespace std;

int main(int argc, const char * argv[]) {
    int n;
    scanf("%d", &n);
    long long a, b, c, sum;
    bool m[n];
    
    for (int i = 0; i < n; i++) {
        scanf("%lld %lld %lld", &a, &b, &c);
        sum = a + b;
        if (a > 0 && b > 0 && sum < 0) m[i] = true;
        else if (a < 0 && b < 0 && sum >= 0) m[i] = false;
        else if (sum > c) m[i] = true;
        else m[i] = false;
    }
    
    for (int i = 0; i < n; i++) {
        if (m[i]) {
            printf("Case #%d: true\n", i+1);
        }else{
            printf("Case #%d: false\n", i+1);
        }
    }
    
    return 0;
}