This is a application of the Trie data structure, with minor extension. The critical part in this problem is to count all the words that have a particualr prefix and the problem has given nice hints to make this extension.
Two functions require to be implemented: add a word to the Trie and search the Trie for all words with a particular prefix.
The code is as follows.
If you are not familiar with Trie, you may refer to this solution first to get the basic idea of it.
1 #include <iostream> 2 3 using namespace std; 4 5 class TrieNode { 6 public: 7 int count; 8 TrieNode* children[26]; 9 TrieNode() { 10 count = 0; 11 for (int i = 0; i < 26; i++) 12 children[i] = NULL; 13 } 14 }; 15 16 class Dictionary { 17 public: 18 Dictionary() { 19 root = new TrieNode(); 20 } 21 22 void insert(char* word) { 23 TrieNode* run = root; 24 for (int i = 0; word[i]; i++) { 25 if (!(run -> children[word[i] - 'a'])) 26 run -> children[word[i] - 'a'] = new TrieNode(); 27 run = run -> children[word[i] - 'a']; 28 run -> count++; 29 } 30 } 31 32 int search(char* prefix) { 33 TrieNode* run = root; 34 for (int i = 0; prefix[i]; i++) { 35 if (run) 36 run = run -> children[prefix[i] - 'a']; 37 else break; 38 } 39 if (!run) return false; 40 return run -> count; 41 } 42 43 private: 44 TrieNode* root; 45 }; 46 47 int main(void) { 48 int dictSize; 49 while (scanf("%d", &dictSize) != EOF) { 50 Dictionary dictionary; 51 char word[20]; 52 for (int i = 0; i < dictSize; i++) { 53 scanf("%s", word); 54 dictionary.insert(word); 55 } 56 int querySize; 57 scanf("%d", &querySize); 58 char prefix[20]; 59 for (int i = 0; i < querySize; i++) { 60 scanf("%s", prefix); 61 printf("%d\n", dictionary.search(prefix)); 62 } 63 } 64 return 0; 65 }