大致题意:给出自从2000 1 1过的天数,以-1结束,输出日期和星期
//以后遇到闰年的问题,坚决用二维数组 #include<stdio.h> #include<string.h> #define N 10010 char date[7][10]={"Sunday","Monday","Tuesday","Wednesday","Thursday","Friday","Saturday"}; int vis[2][12]={31,28,31,30,31,30,31,31,30,31,30,31,31,29,31,30,31,30,31,31,30,31,30,31}; //vis[0]表示非闰 int leap[N]; void isleap() { int i,j; memset(leap,0,sizeof(leap)); for(i=2000;i<N;i++) if(i%4==0&&i%100!=0||i%400==0) leap[i]=1; } int main() { int i,j,k; int num; int flag;//星期代表元 int year; isleap(); while(scanf("%d",&num),num!=-1) { k=num; flag=(num+6)%7;//第一天星期6,先求flag是因为,后来num要改变 for(i=2000;num>=(leap[i]==1?366:365);i++)//第一次判断便不成立时,i没有自增,以后就自增了 { if(leap[i]) num-=366; else num-=365; } // printf("i=%d\n",i); for(j=0;num>=vis[leap[i]][j]&&j<12;j++)//月份 { num-=vis[leap[i]][j]; } printf("%d-%02d-%02d %s\n",i,j+1,num+1,date[flag]);//注意6要输出为06 } return 0; }