点击打开链接uva 1329
思路: 带权并查集
分析:
1 看懂题目就是切菜了
代码:
#include<cstdio>
#include<cstring>
#include<iostream>
#include<algorithm>
using namespace std;
const int MAXN = 20010;
int n;
int father[MAXN];
int rank[MAXN];
void init(){
memset(rank , 0 , sizeof(rank));
for(int i = 1 ; i < MAXN ; i++)
father[i] = i;
}
int find(int x){
if(father[x] == x)
return x;
int tmp = father[x];
father[x] = find(father[x]);
rank[x] += rank[tmp];
return father[x];
}
int main(){
int Case;
char c;
int x , y;
scanf("%d" , &Case);
while(Case--){
init();
scanf("%d%*c" , &n);
while(scanf("%c" , &c) && c != 'O'){
if(c == 'E'){
scanf("%d%*c" , &x);
int tmp = find(x);
printf("%d\n" , rank[x]);
}
else{
scanf("%d%d%*c" , &x , &y);
int fx = find(x);
int fy = find(y);
if(fx != fy){
father[fx] = fy;
rank[fx] = abs(x-y)%1000+rank[y]-rank[x];
}
}
}
}
return 0;
}