要求:编写一个脚本读入一些整数，分别输出这些整数中奇数的个数和偶数的个数，并输出0的个数.
实现脚本如下:
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#!/bin/bash
#charpter_8-12
declare
-a arr2
echo
"Please input some integer numbers seprated by SPACE:"
read
-a arr2
counter_odd=0
counter_even=0
counter_0=0
for
i
in
"${arr2[@]}"
do
if
[[ i -
ne
0 ]]
then
if
[[ i%2 -
eq
0 ]]
then
let
counter_even+=1
else
let
counter_odd+=1
fi
else
let
counter_0+=1
fi
done
echo
"偶数个数:$counter_even"
echo
"奇数个数:$counter_odd"
echo
"0的个数:$counter_0"
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脚本的执行效果:
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[root@localhost charpter8]
# sh 8-12
Please input some integer numbers seprated by SPACE:
10 11 0 12 13 0 14 15 0
偶数个数:3
奇数个数:3
0的个数:3
[root@localhost charpter8]
# sh 8-12
Please input some integer numbers seprated by SPACE:
-12 -13 -14 0 12 13 14 15 0 17
偶数个数:4
奇数个数:4
0的个数:2
[root@localhost charpter8]
#
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可以看到准确的输出了结果.
本文转自 marbury 51CTO博客，原文链接:http://blog.51cto.com/magic3/1429696
