入门使用
# 示例代码 warframe = ["saryn", "wisp", "volt"] counts = [len(n) for n in warframe] for i,j in zip(warframe,counts): print(f"name is {i}, len is {j}") # name is saryn, len is 5 # name is wisp, len is 4 # name is volt, len is 4
每次循环时，zip函数会从迭代器里获取各自的下一个元素，并把这些值放在一个元组里面。而这个元组可以拆分到 for 语句里的变量中。
处理迭代元素数量不一致问题
如果两个可迭代元素数量不一致，那么只要其中任何一个迭代器遍历结束，zip函数就会终止。
warframe = ["saryn", "wisp", "volt"] fans = [10,20,30,40] for i,j in zip(warframe,fans): print(i,j) # saryn 10 # wisp 20 # volt 30
这时候应该换用zip_longest函数，它封装在itertools模块中。
from itertools import zip_longest for i,j in zip_longest(warframe,fans): print(i,j) # saryn 10 # wisp 20 # volt 30 # None 40
迭代更多可迭代对象
warframe = ["saryn", "wisp", "volt"] counts = [len(n) for n in warframe] fans = [10,20,30,40] for i,j,k in zip(warframe,counts,fans): print(i,j,k) # saryn 5 10 # wisp 4 20 # volt 4 30
