题目链接&xff1a;...略。解题思路&xff1a;注意 2 种生成序列方法。AC 代码-解决方案(1) WITH t1 as SELECT 1 as a UNION ALL SELECT 2 ...(SELECT customer_id FROM Customers ORDER BY customer_id DESC LIMIT 1)
(SELECT 1 AS `X`)AS `SingleRowTable6`)AS `UnionAll5` UNION ALL SELECT 59 AS `C1` FROM(SELECT 1 AS `X`)AS `SingleRowTable7`)AS `UnionAll6` UNION ALL SELECT 18 AS `C1` FROM(SELECT 1 AS `X`)AS `...
为select添加事件，当选择其中一项时触发 ("#select_id").change(function(){ });获取select选择的Text var checkText=$("#select_id").find("option:selected").text();获取Select选择的Value var checkValue=$("#...
select emp.ename,emp.sal,emp.deptno from emp,(select max(sal)max_sal,deptno from emp group by deptno)t where emp.sal=t.max_sal and emp.deptno=t.deptno;求部门平均工资等级 select s.grade,t.deptno,t.avg_...
(SELECT id,hanzi FROM pinyin WHERE 1 AND(id=417))UNION ALL(SELECT id,hanzi FROM pinyin WHERE 1 AND(id=670))UNION ALL(SELECT id,hanzi FROM pinyin WHERE 1 AND(id=874))UNION ALL(SELECT id,hanzi FROM ...
(select 0 as num union all select 1 union all select 2 union all select 3 union all select 4 union all select 5 union all select 6 union all select 7 union all select 8 union all select 9)n2,(select 0...
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select a.Date from(select curdate()-INTERVAL(a.a+(10*b.a)+(100*c.a)+(1000*d.a))DAY as Date from(select 0 as a union all select 1 union all select 2 union all select 3 union all select 4 union all ...
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SELECT SUBSTRING_INDEX(SUBSTRING_INDEX(t.values,',',n.n),',',-1)value FROM table1 t CROSS JOIN(SELECT a.N+b.N*10+1 n FROM(SELECT 0 AS N UNION ALL SELECT 1 UNION ALL SELECT 2 UNION ALL SELECT 3 UNION ...
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CREATE OR REPLACE VIEW generator_16 AS SELECT 0 n UNION ALL SELECT 1 UNION ALL SELECT 2 UNION ALL SELECT 3 UNION ALL SELECT 4 UNION ALL SELECT 5 UNION ALL SELECT 6 UNION ALL SELECT 7 UNION ALL SELECT ...
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(SELECT 0 AS b UNION SELECT 8)b4,(SELECT 0 AS b UNION SELECT 16)b5,(SELECT 0 AS b UNION SELECT 32)b6,(SELECT 0 AS b UNION SELECT 64)b7,(SELECT 0 AS b UNION SELECT 128)b8,(SELECT 0 AS b UNION SELECT ...
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var1:=SELECT[ALL|DISTINCT]select_expr,select_expr,. FROM table3 [WHERE where_condition];var2:=SELECT[ALL|DISTINCT]select_expr,select_expr,. FROM table4 [WHERE where_condition];var3:=SELECT[ALL|...
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SELECT COUNT(u.userID)AS total,m.month FROM(SELECT 'Jan' AS MONTH UNION SELECT 'Feb' AS MONTH UNION SELECT 'Mar' AS MONTH UNION SELECT 'Apr' AS MONTH UNION SELECT 'May' AS MONTH UNION SELECT 'Jun' AS ...
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SELECT*FROM SELECT a.key,b.value FROM SELECT*FROM src WHERE key IS NOT NULL)a JOIN SELECT*FROM src2 WHERE value>0)b ON a.key=b.key c UNION ALL SELECT*FROM SELECT a.key,b.value FROM SELECT*FROM src ...
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t1.month,t1.md,coalesce(SUM(t1.amount+t2.amount),0)AS total from(select DATE_FORMAT(a.Date,"%b")as month,DATE_FORMAT(a.Date,"%m-%Y")as md,'0' as amount from(select curdate()-INTERVAL(a.a+(10*b.a)+(100...
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CREATE VIEW generator_16 AS SELECT 0 n UNION ALL SELECT 1 UNION ALL SELECT 2 UNION ALL SELECT 3 UNION ALL SELECT 4 UNION ALL SELECT 5 UNION ALL SELECT 6 UNION ALL SELECT 7 UNION ALL SELECT 8 UNION ALL...
