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问题

使用pxf访问外接表,查询提示错误

hawqgsdb=# select count(*) from retail_demo.customers_dim_pxf;ERROR: remote component error (500) from '192.168.21.3:51...
jasligea 2019-12-01 20:26:10 499 浏览量 回答数 1

问题

Pytorch中的LSTM:如何添加/更改序列长度维度?

我在pytorch中运行LSTM,但据我所知,它只取序列长度= 1。当我将序列长度整形为4或其他数字时,就会得到输入和目标长度不匹配的错误。如果我同时对输入和目标进行整形,那么...
kun坤 2019-12-27 17:46:33 540 浏览量 回答数 1

回答

public class Findareas{ public static void main (String []agrs){ Figure f= new Figure(10 , 10); Rectangle r= new Rectangle(9 , 5); Figure figref; figref=f; System.out.println("Area is :"+figref.area()); figref=r; System.out.println("Area is :"+figref.area()); } } class Figure{ double dim1; double dim2; Figure(double a , double b) { dim1=a; dim2=b; } Double area() { System.out.println("Inside area for figure."); return(dim1*dim2); } } class Rectangle extends Figure { Rectangle(double a, double b) { super(a ,b); } Double area() { System.out.println("Inside area for rectangle."); return(dim1*dim2); } } 以上代码运行输出结果为: Inside area for figure. Area is :100.0 Inside area for rectangle. Area is :45.0
珍宝珠 2020-02-12 19:56:16 0 浏览量 回答数 0

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回答

这是我为几乎相同的堆栈编写的(我们需要标准化硬件的制造商名称,并且有各种各样的变体)。不过,这是客户端(准确地说是VB.Net)-并使用Levenshtein距离算法(已修改,以获得更好的结果): Public Shared Function FindMostSimilarString(ByVal toFind As String, ByVal ParamArray stringList() As String) As String Dim bestMatch As String = "" Dim bestDistance As Integer = 1000 'Almost anything should be better than that! For Each matchCandidate As String In stringList Dim candidateDistance As Integer = LevenshteinDistance(toFind, matchCandidate) If candidateDistance < bestDistance Then bestMatch = matchCandidate bestDistance = candidateDistance End If Next Return bestMatch End Function 'This will be used to determine how similar strings are. Modified from the link below... 'Fxn from: http://ca0v.terapad.com/index.cfm?fa=contentNews.newsDetails&newsID=37030&from=list Public Shared Function LevenshteinDistance(ByVal s As String, ByVal t As String) As Integer Dim sLength As Integer = s.Length ' length of s Dim tLength As Integer = t.Length ' length of t Dim lvCost As Integer ' cost Dim lvDistance As Integer = 0 Dim zeroCostCount As Integer = 0 Try ' Step 1 If tLength = 0 Then Return sLength ElseIf sLength = 0 Then Return tLength End If Dim lvMatrixSize As Integer = (1 + sLength) * (1 + tLength) Dim poBuffer() As Integer = New Integer(0 To lvMatrixSize - 1) {} ' fill first row For lvIndex As Integer = 0 To sLength poBuffer(lvIndex) = lvIndex Next 'fill first column For lvIndex As Integer = 1 To tLength poBuffer(lvIndex * (sLength + 1)) = lvIndex Next For lvRowIndex As Integer = 0 To sLength - 1 Dim s_i As Char = s(lvRowIndex) For lvColIndex As Integer = 0 To tLength - 1 If s_i = t(lvColIndex) Then lvCost = 0 zeroCostCount += 1 Else lvCost = 1 End If ' Step 6 Dim lvTopLeftIndex As Integer = lvColIndex * (sLength + 1) + lvRowIndex Dim lvTopLeft As Integer = poBuffer(lvTopLeftIndex) Dim lvTop As Integer = poBuffer(lvTopLeftIndex + 1) Dim lvLeft As Integer = poBuffer(lvTopLeftIndex + (sLength + 1)) lvDistance = Math.Min(lvTopLeft + lvCost, Math.Min(lvLeft, lvTop) + 1) poBuffer(lvTopLeftIndex + sLength + 2) = lvDistance Next Next Catch ex As ThreadAbortException Err.Clear() Catch ex As Exception WriteDebugMessage(Application.StartupPath , [Assembly].GetExecutingAssembly().GetName.Name.ToString, MethodBase.GetCurrentMethod.Name, Err) End Try Return lvDistance - zeroCostCount End Function
心有灵_夕 2019-12-29 12:50:04 0 浏览量 回答数 0

回答

好吧,既然没有帮助,我就解决了这个问题,终于使它起作用了。这是我的工作代码。 从Picturebox中保存到MySQL(pbPicture) Dim filename As String = txtName.Text + ".jpg" Dim FileSize As UInt32 conn.Close() Dim mstream As New System.IO.MemoryStream() PbPicture.Image.Save(mstream, System.Drawing.Imaging.ImageFormat.Jpeg) Dim arrImage() As Byte = mstream.GetBuffer() FileSize = mstream.Length Dim sqlcmd As New MySqlCommand Dim sql As String mstream.Close() sql = "insert into [your table] (picture, filename, filesize) VALUES(@File, @FileName, @FileSize)" Try conn.Open() With sqlcmd .CommandText = sql .Connection = conn .Parameters.AddWithValue("@FileName", filename) .Parameters.AddWithValue("@FileSize", FileSize) .Parameters.AddWithValue("@File", arrImage) .ExecuteNonQuery() End With Catch ex As Exception MsgBox(ex.Message) Finally conn.Close() End Try 从MySQL db加载回到Picturebox Dim adapter As New MySqlDataAdapter adapter.SelectCommand = Cmd data = New DataTable adapter = New MySqlDataAdapter("select picture from [yourtable]", conn) 注意!!只能在Picturebox中放置一张图片,因此很明显,此查询只能为您返回一张记录 commandbuild = New MySqlCommandBuilder(adapter) adapter.Fill(data) Dim lb() As Byte = data.Rows(0).Item("picture") Dim lstr As New System.IO.MemoryStream(lb) PbPicture.Image = Image.FromStream(lstr) PbPicture.SizeMode = PictureBoxSizeMode.StretchImage lstr.Close()来源:stack overflow
保持可爱mmm 2020-05-17 12:56:49 0 浏览量 回答数 0

回答

Private Function F(n As Long) As Long If n > 2 Then F = F(n - 1) + F(n - 2) Else F = 1 End If End Function Private Sub Command1_Click() Dim a As String Dim i as long Dim n as long Dim sum as long a = InputBox("输入斐波那契数列项数", "输入") n = Clng(a) Cls For i=1 to n sum = sum + F(i) Next Print "斐波那契数列前";Cstr(n);"项和:";sum End Sub
云篆 2019-12-02 01:24:24 0 浏览量 回答数 0

问题

impala报错:Could not initialize class org.?400报错

impala-shell启动后,执行show tables和show databases都正常,执行表查询,就报错,具体错误信息如下: [tjxt11:21000] &...
爱吃鱼的程序员 2020-06-08 09:51:34 0 浏览量 回答数 1

回答

具有基本安全性的密码存储过程非常简单: 用盐散列密码 为每个用户/密码使用不同的盐 将带有哈希密码的盐存储在数据库中 当他们尝试登录时,请通过相同的方法运行尝试的PW。比较结果。 如果他们输入了正确的密码,则散列的PW将匹配。散列可以保护用户免受攻击,也可以保护看门人members在显示表格的屏幕旁走动。 撒盐和散列PW ' salt size is 32 (0-31 Private Const SaltSize As Integer = 31 ... Dim dbPW As String = TextBox1.Text Dim dbSalt = CreateNewSalt(SaltSize) ' eg: "dsEGWpJpwfAOvdRZyUo9rA==" Dim SaltedPWHash As String = GetSaltedHash(dbPW, dbSalt) ' examples: ' using SHA256: bbKN8wYYgoZmNaG3IsQ2DPS2ZPIOnenl6i5NwUmrGmo= ' using SHA512: ' 0vqZWBIbOlyzL25l9iWk51CxxJTiEM6QUZEH1ph+/aNp+lk4Yf8NYv8RLhYtbqCNpOqO3y8BmM+0YWtbAhE+RA==" 将PW哈希和盐存储为用户记录的一部分。盐不是秘密的,但是当用户更改密码时可以更改盐。 比较登录尝试 ' check if PW entered equals DB Dim pwTry = TextBox2.Text ' hash the login attempt using the salt stored in the DB Dim pwLogin = GetSaltedHash(pwTry, dbSalt) ' compare the hash of what they entered to whats in the DB: If String.Compare(SaltedPWHash, pwLogin, False) = 0 Then ' okay! Console.Beep() End If 如果用户输入相同的PW,则应产生相同的哈希,就这么简单。哈希码并不那么复杂: 哈希方法 Private Function GetSaltedHash(pw As String, salt As String) As String Dim tmp As String = pw & salt ' or SHA512Managed Using hash As HashAlgorithm = New SHA256Managed() ' convert pw+salt to bytes: Dim saltyPW = Encoding.UTF8.GetBytes(tmp) ' hash the pw+salt bytes: Dim hBytes = hash.ComputeHash(saltyPW) ' return a B64 string so it can be saved as text Return Convert.ToBase64String(hBytes) End Using End Function Private Function CreateNewSalt(size As Integer) As String ' use the crypto random number generator to create ' a new random salt Using rng As New RNGCryptoServiceProvider ' dont allow very small salt Dim data(If(size < 7, 7, size)) As Byte ' fill the array rng.GetBytes(data) ' convert to B64 for saving as text Return Convert.ToBase64String(data) End Using End Function 使用诸如GUID(System.Guid.NewGuid.ToString)之类的东西作为引诱对象是很诱人的,但是使用密码随机数生成器并不难。 与哈希密码一样,由于编码,返回字符串更长。 每次用户更改密码时都要创建一个新的盐。不要使用全局盐,它会达到目的。 您还可以多次对PW进行哈希处理。关键部分是要在被攻击时花很长时间才能尝试所有各种组合。 这些功能是Shared/ static类成员的理想人选。 还要注意,肯尼斯(Kenneth)链接的文章值得一读。 请注意,本文提到的The salt should be stored in the user account table alongside the hash 这并不意味着您必须Salt在数据库中有一列。您可以在链接的文章中看到以下内容: Dim dbPW As String = TextBox1.Text Dim dbSalt = CreateNewSalt(SaltSize) ' get the salted PW hash Dim SaltedPWHash As String = GetSaltedHash(dbPW, dbSalt) ' store salt with the hash: SaltedPWHash = String.Format("{0}:{1}", dbSalt, dbPW) ' salt + ":" + hashed PW now ready to store in the db 要从哈希密码中分离出盐: Dim SaltAndPWHash = rdr.Item("PWHash").ToString() Dim split = SaltAndPWHash.Split(":"c) ' split on ":" Dim Salt = split(0) ' element(0) == salt Dim StoredPWHash = split(1) ' element(1) == hashed PW 您需要两个部分:在对PW中的尝试登录进行哈希处理之后,将其与进行比较split(1)。来源:stack overflow
保持可爱mmm 2020-05-17 14:28:58 0 浏览量 回答数 0

问题

将图像存储到数据库Blob;从数据库检索到Picturebox?mysql

您好,我在较早之前发布了此内容,并获得了一些帮助,但仍然没有有效的解决方案。由于最后的问与答,我确定我的“保存到数据库”代码以及“检索到图片”代码有问题。即使我手动将图片保存在数据库中...
保持可爱mmm 2020-05-17 12:46:49 4 浏览量 回答数 1

问题

与linux服务器上的mongd实例连接不上

可以使用mongo xxx.xxx.xxx.xxx连接上客户端进行操作, 但是进行Balancer时, 错误提示如下:balancer move failed: { cause: { active: false, ns: "testdb.u...
落地花开啦 2019-12-01 20:01:36 1348 浏览量 回答数 0

问题

Update语句中的表名不能用参数代替吗

asp连接access数据库中 dim strSql, strSql2 strSql="Update 东方不败 Set Sfhwhy='Y' where name='"&amp;hy&amp;"'" conn2.Execute(strSql...
小旋风柴进 2019-12-01 19:47:19 817 浏览量 回答数 1

问题

程序从轻云服务器上搬到ECS服务器后,网站打开显示路径不正确

<% dim db,db2 const DatabaseType="ACCESS"     db="../ds/sd.mdb" db2="da/et.mdb" ...
风中的男人 2019-12-01 22:04:23 4991 浏览量 回答数 2

回答

这里有一个程序 希望可以帮到你 vb写的Koch雪花递归算法Const pi = 3.14159 Private Sub Form_Click() ScaleTop = 300 ScaleLeft = -75 ScaleWidth = 400 ScaleHeight = -300 Call fractal(50 + 30, 150, 110 + 30, 254, 1) Call fractal(110 + 30, 254, 170 + 30, 150, 1) Call fractal(170 + 30, 150, 50 + 30, 150, 1) End Sub Sub fractal(ax As Single, ay As Single, bx As Single, by As Single, s As Integer) If (bx - ax) * (bx - ax) + (by - ay) * (by - ay) < s Then Line (ax, ay)-(bx, by) Else Dim cx As Single, cy As Single Dim dx As Single, dy As Single Dim ex As Single, ey As Single Dim l As Single Dim alpha As Single cx = ax + (bx - ax) / 3 cy = ay + (by - ay) / 3 ex = bx - (bx - ax) / 3 ey = by - (by - ay) / 3 Call fractal(ax, ay, cx, cy, s) Call fractal(ex, ey, bx, by, s) l = Sqr((ex - cx) * (ex - cx) + (ey - cy) * (ey - cy)) alpha = Atn((ey - cy) / (ex - cx)) If (alpha >= 0 And (ex - cx) < 0) Or (alpha <= 0 And (ex - cx) < 0) Then alpha = alpha + pi End If dy = cy + Sin(alpha + pi / 3) * l dx = cx + Cos(alpha + pi / 3) * l Call fractal(cx, cy, dx, dy, s) Call fractal(dx, dy, ex, ey, s) End IfEnd Sub 祝你好运俄
知与谁同 2019-12-02 01:24:52 0 浏览量 回答数 0

回答

'创建一个显示textBox的列() Dim col1 As DataGridViewTextBoxColumn =New DataGridViewTextBoxColumn() col1.Name = "Name" col1.HeaderText = "姓名" '设置标题中显示的文本 Dim col3 As DataGridViewTextBoxColumn = NewDataGridViewTextBoxColumn() col3.Name = "sex" col3.HeaderText = "性别" '将新建的列添加到控件中 DataGridView1.Columns.Add(col1) DataGridView1.Columns.Add(col3) '添加行 '创建新行 Dim row As DataGridViewRow = NewDataGridViewRow() row.CreateCells(DataGridView1) '设置单元格的值 row.Cells(0).Value = "张三" row.Cells(1).Value = "男" DataGridView1.Rows.Add(row) '添加第二行 im row1 As String() = {"李四", "男"} DataGridView1.Rows.Add(row1)
a123456678 2019-12-02 02:19:19 0 浏览量 回答数 0

问题

ODPS,表:dim_xxxx,正在使用的时候,忽然没有了。

ODPS,表:dim_xxxx,正在使用的时候,忽然没有了。我们在命令行用show p;查看今天运行的SQL,没有发现DROP语句,我们查不到这个表什么时候被删除请问是谁删了这个表?在什么时间?...
123ya 2019-12-01 20:11:54 907 浏览量 回答数 1

问题

MaxCompute表dim_xxxx正在使用时找不到了。使命令行show p;没有查到相关sql

MaxCompute表dim_xxxx正在使用时找不到了。使命令行show p;查看运行的SQL,没有发现DROP语句,这个表是谁在什么时间删除的?...
montos 2020-05-27 16:31:23 3 浏览量 回答数 1

问题

编写VB.Net代码以过滤SQL Server表属性

我的SQL Server表中有几列,并希望过滤“承包商”列。用户可以在“承包商”列中选择两个名称“ Namal”和“ other”,如屏幕截图所示。 我想要的是仅对“ Namal”而不是“ other”获得“金...
LiuWH 2020-01-04 11:12:26 2 浏览量 回答数 1

回答

Private Sub Command1_Click() Dim a(10) As Integer Dim b As Integer Dim i As Integer Dim j As Integer Dim k As Integer For i = 1 To 10     a(i) = Int(Rnd * 90 + 10)     Print a(i); Next i Print For i = 1 To 9     k = i     For j = k + 1 To 10         If a(j) < a(k) Then k = j     Next j     If a(i) > a(k) Then         b = a(i)         a(i) = a(k)         a(k) = b     End If Next i For i = 1 To 10 Print a(i); Next i Print End Sub
liujae 2019-12-02 01:19:18 0 浏览量 回答数 0

回答

就是比较数值,把大的或小的放在前面 比如,有一个数组a()包含{5,7,3,9,12,15,56}7个数 dim t as integer for i=0 to a.count-1 for j=i+1 to a.count-1 t=a(i) if a(i)<a(j) then a(i)=a(j) a(j)=t next next 这时比较排序法 下面是冒泡排序 Private Sub Form_Load()   Dim a,c As Variant   Dim i As Integer,j As Integer,temp As Integer,bSwap As Boolean   a = Array(17,45,12,80,50)   For j = 0 To UBound(a) - 1   bSwap = False   For i = 0 To UBound(a) - 1   If (a(i) > a(i + 1)) Then '若是递减,改为a(i)<a(i+1)   temp = a(i)   a(i) = a(i + 1)   a(i + 1) = temp   bSwap = True   End If   Next   If bSwap = False Then   Exit For   End If   Next   For Each c In a   Debug.Print c;   Next   End Sub
青衫无名 2019-12-02 01:19:18 0 浏览量 回答数 0

问题

通过码栈访问自己搭建的webservice

码栈对页面元素的处理已经很完整,但是是在实现更复杂的后台逻辑或调用其它平台接口时,却没有能更好的解决 所以自己搭建了个webservice的服务,码栈通过调用自己的服务,再由自己的服务...
西瓜皮lcy 2019-12-01 22:01:53 2757 浏览量 回答数 2

回答

【VC里面什么叫拉锯法排序?】所谓“拉锯式排序法”是这一遍把最小的元素从下到上送到最上的位置,下一遍则是从上到下把最大的元素送到最下的位置。以下是引用片段:   Option Base 1   Private Sub Command1_Click()   Dim a(10) As Integer,i As Integer   For i = 1 To 10   a(i) = Int(Rnd * 10)+1   Text1 = Text1 & Str(a(i))   Next i   Call shaker_sort(a)   For i = 1 To 10   Text2 = Text2 & Str(a(i))   Next i   End Sub   Private Sub Shaker_sort(k() As Integer)   Dim i As Integer,c As Integer,d As Integer   Dim t As Integer   c = 1   d = (1)   Do   For  (2) Step-1   If k(i=1)>k(i) Then   t = k(i-1):k(i-1) = k(i):k(i) = t   End If   Next i   (3)   For i = c+1 To d   If (4) Then   t = k(i-1):k(i-1) = k(i):k(i) = t   End If   Next i   d = d-1   Loop While  (5)   End Sub
boxti 2019-12-02 01:19:08 0 浏览量 回答数 0

回答

gram rem (c) W.Buchanan rem Jan 2002 Function check_prime(ByVal val As Long) As Boolean Dim primes primes = Array(1, 2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43, 47, 53, 59, 61, 67, 71, 73, 79, 83, 89, 97, 101, 103, 107, 109, 113, 127, 131, 137, 139, 149, 151, 157, 163, 167, 173, 179, 181, 191, 193, 197, 199, 211, 223, 227, 229, 233, 239, 241, 251, 257, 263, 269, 271, 277, 281, 283, 293, 307, 311, 313, 317, 331, 337, 347, 349, 353, 359, 367, 373, 379, 383, 389, 397) check_prime = False For i = 0 To 78 If (val = primes(i)) Then prime = True End If Next i check_prime = prime End Function Function decrypt(ByVal c, ByVal n, ByVal d As Long) Dim i, g, f As Long On Error GoTo errorhandler If (d Mod 2 = 0) Then g = 1 Else g = c End If For i = 1 To d / 2 f = c * c Mod n g = f * g Mod n Next i decrypt = g Exit Function errorhandler: Select Case Err.Number ' Evaluate error number. Case 6 status.Text = "Calculation overflow, please select smaller values" Case Else status.Text = "Calculation error" End Select End Function Function getD(ByVal e As Long, ByVal PHI As Long) As Long Dim u(3) As Long Dim v(3) As Long Dim q, temp1, temp2, temp3 As Long u(0) = 1 u(1) = 0 u(2) = PHI v(0) = 0 v(1) = 1 v(2) = e While (v(2) <> 0) q = Int(u(2) / v(2)) temp1 = u(0) - q * v(0) temp2 = u(1) - q * v(1) temp3 = u(2) - q * v(2) u(0) = v(0) u(1) = v(1) u(2) = v(2) v(0) = temp1 v(1) = temp2 v(2) = temp3 Wend If (u(1) < 0) Then getD = (u(1) + PHI) Else getD = u(1) End If End Function Function getE(ByVal PHI As Long) As Long Dim great, e As Long great = 0 e = 2 While (great <> 1) e = e + 1 great = get_common_denom(e, PHI) Wend getE = e End Function Function get_common_denom(ByVal e As Long, ByVal PHI As Long) Dim great, temp, a As Long If (e > PHI) Then While (e Mod PHI <> 0) temp = e Mod PHI e = PHI PHI = temp Wend great = PHI Else While (PHI Mod e <> 0) a = PHI Mod e PHI = e e = a Wend great = e End If get_common_denom = great End Function Private Sub show_primes() status.Text = "1" no_primes = 1 For i = 2 To 400 prime = True For j = 2 To (i / 2) If ((i Mod j) = 0) Then prime = False End If Next j If (prime = True) Then no_primes = no_primes + 1 status.Text = status.Text + ", " + Str(i) End If Next i status.Text = status.Text + vbCrLf + "Number of primes found:" + Str(no_primes) End Sub Private Sub Command1_Click() Dim p, q, n, e, PHI, d, m, c As Long p = Text1.Text q = Text2.Text If (check_prime(p) = False) Then status.Text = "p is not a prime or is too large, please re-enter" ElseIf (check_prime(q) = False) Then status.Text = "q is not a prime or is too large, please re-enter" Else n = p * q Text3.Text = n PHI = (p - 1) * (q - 1) e = getE((PHI)) d = getD((e), (PHI)) Text4.Text = PHI Text5.Text = d Text6.Text = e m = Text7.Text c = (m ^ e) Mod n Text8.Text = c m = decrypt(c, n, d) Text9.Text = m Label12.Caption = "Decrypt key =<" + Str(d) + "," + Str(n) + ">" Label13.Caption = "Encrypt key =<" + Str(e) + "," + Str(n) + ">" End If End Sub Private Sub Command2_Click() End End Sub Private Sub Command3_Click() frmBrowser.Show End Sub Private Sub Command4_Click() Call show_primes End Sub
美人迟暮 2019-12-02 01:27:04 0 浏览量 回答数 0

回答

Option Base 1 Private Sub Command1_Click() Dim a Dim b As Integer Dim i As Integer Dim j As Integer a = Array(6, 3, 7, 8, 2, 1) Print "排序前为"; For i = 1 To 6 Print a(i); Next i For i = 1 To 5   For j = 1 To 6 - i      If a(j) > a(j + 1) Then       b = a(j + 1)       a(j + 1) = a(j)       a(j) = b       End If     Next j  Next i  Print  Print "排序后为";  For i = 1 To 6    Print a(i);  Next i End Sub
祁同伟 2019-12-02 01:17:45 0 浏览量 回答数 0

问题

识别在编写SQL时需要改进VBA代码的区域

我正在寻找优化以下模块的方法。 我将经常需要用我在excel工作表/工作簿中收到的带有大型数据集的数据库来更新数据库。我已经制作了一个模块,可以将工作表导入到指定的数据库中。在这里使用stringbuilder类- htt...
心有灵_夕 2019-12-22 13:48:37 0 浏览量 回答数 0

回答

Private Sub Command1_Click() Dim a As Integer, b As Integer, c As Integer Dim p As Long a = Val(InputBox("A=")) b = Val(InputBox("B=")) c = Val(InputBox("C=")) p = jc(a) + jc(b) + jc(c) Print a & "!+" & b & "!+" & c & "!=" & p End Sub Function jc(n As Integer) If n > 1 Then jc = n * jc(n - 1) Else jc = 1 End If End Function
一键天涯 2019-12-02 01:24:49 0 浏览量 回答数 0

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Dim n(9) As Integer For i = 0 To 9 Randomize '初始化 n(i) = Rnd * 100 '赋随机值 Next i Dim temp As Integer '用作改变位置临时存储 For i = 0 To 8 If n(i) > n(i + 1) Then '判断是否前一位大于后一位 temp = n(i) n(i) = n(i + 1) n(i + 1) = temp i = -1 '为了更准确,让它重新开始 End If Next i For i = 0 To 9 Print "第" & i + 1 & "位:" & n(i) '输出 Next i
boxti 2019-12-02 01:19:20 0 浏览量 回答数 0

问题

关于asp josn 接到参数 执行 sql语句 报错问题

&lt;% Dim member Set member = jsObject() dim dbconnection,uplist,DBPath,SQL,Sort,Lbound,Ubound Dim id=request("jsoncallb...
小旋风柴进 2019-12-01 19:47:08 885 浏览量 回答数 1

问题

如何将matlab代码转换成python代码?(

我刚接触python,并尝试在python 3中转换这个优化的matlab代码,但在python中的结果是完全不同的。有人可以重新检查代码并提供适当的解决方案。matlab代码显示优化值为10^-24,pytho...
kun坤 2019-12-25 21:47:26 498 浏览量 回答数 1

问题

python如何用零填充numpy数组

我想知道如何使用python 2.6.6和numpy版本1.5.0用零填充2D numpy数组。抱歉! 但是这些是我的局限性。因此我不能使用np.pad。例如,我想a用零填充以使其形状匹配b。我想这样做的原因是我可以这样做&#...
保持可爱mmm 2020-02-09 14:10:16 100 浏览量 回答数 1

问题

Excel VBA与MySQL远程数据库的连接字符串不起作用

我在远程计算机上安装了MySQL服务器。 我试图通过excel VBA连接到它-我可以通过excels内置数据库连接工具成功连接到它并复制连接字符串,但是VBA讨厌该连接字符串。这是我的代码和错误 Dim conn As ...
保持可爱mmm 2019-12-01 21:57:54 11 浏览量 回答数 0

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