rt,本人在服务器上写了一个servlet来接收post请求,用网页的form表单测试了一下可以同时接收文本框的内容和文件的上传,但是我想用java程序来发送这个post请求,查了很多,要么只有文本或者只有文件传输,没有同时传送文本和文件的,还有我想服务器返回给客户端的里面也同时包含文本或者文件,怎么做
服务端:
public partial class _Default : System.Web.UI.Page
{
private string id = "";
private string userName = "";
private string type = "";
private string fileName = "";
//文件长度
private long contentLength = 0;
private static readonly string filePath = ConfigurationManager.AppSettings["filePath"];
protected void Page_Load(object sender, EventArgs e)
{
if (!IsPostBack)
{
id = Request["id"];
userName = Request["user"];
type = Request["type"];
fileName = Request.Headers["FileName"];
writeFile();
}
}
/// <summary>
/// 上传文件
/// </summary>
private void writeFile()
{
try
{
Stream stream = Request.InputStream;
contentLength = stream.Length;
string currentFilePath = filePath + userName;
if (!Directory.Exists(currentFilePath))
{
Directory.CreateDirectory(currentFilePath);
}
FileStream fileStream = File.Create(currentFilePath + @"\" + fileName);
//每次读取的1024个字节
byte[] bytes = new byte[1024];
int numReadByte = 0;
while ((numReadByte = stream.Read(bytes, 0, 1024)) != 0)
{
fileStream.Write(bytes, 0,numReadByte);
}
//关闭流
stream.Close();
fileStream.Close();
}
Java文件上传客户端示例:
/**
*
* 只是写的一个示例,filePath,和FileName根据需要进行调整。
*/
public class MyTest {
/**
* @param args
*/
public static void main(String[] args) {
// TODO Auto-generated method stub
String str="http://localhost:2906/Default.aspx?id=1&user=2&type=3";
String filePath="D:\\Wildlife.wmv";
String fileName="Wildlife.wmv";
try {
URL url=new URL(str);
HttpURLConnection connection=(HttpURLConnection)url.openConnection();
connection.setDoInput(true);
connection.setDoOutput(true);
connection.setRequestMethod("POST");
connection.addRequestProperty("FileName", fileName);
connection.setRequestProperty("content-type", "text/html");
BufferedOutputStream out=new BufferedOutputStream(connection.getOutputStream());
//读取文件上传到服务器
File file=new File(filePath);
FileInputStream fileInputStream=new FileInputStream(file);
byte[]bytes=new byte[1024];
int numReadByte=0;
while((numReadByte=fileInputStream.read(bytes,0,1024))>0)
{
out.write(bytes, 0, numReadByte);
}
out.flush();
fileInputStream.close();
//读取URLConnection的响应
DataInputStream in=new DataInputStream(connection.getInputStream());
} catch (Exception e) {
e.printStackTrace();
}
}
}