keywords=["dsaa","Asd","sadc","Gdfd","gdfdd","gaf","gabdddddd","eg"] print dict([(i[0],list(i[1]))for i in groupby(sorted(keywords),lambda x:x[0].lower())]) Javascript: nth element in the fibonacci ...
例题:A→BCc|gDBA→BCc|gDB B→bCDE|εB→bCDE|ε C→DaB|caC→DaB|ca D→dD|εD→dD|ε E→gAf|cE→gAf|c 非终结符 FIRST FOLLOW A {a,b,c,d,g} {f,#} B {b,εε} {a,c,d,g,f,#} C {a,c,d} {c,d,g} D {d,εε} ...