Design Tutorial: Learn from Math

简介: Design Tutorial: Learn from Math

文章目录

一、Design Tutorial: Learn from Math

总结


一、Design Tutorial: Learn from Math

本题链接:Design Tutorial: Learn from Math


题目:

A. Design Tutorial: Learn from Math

time limit per test1 second

memory limit per test256 megabytes

inputstandard input

outputstandard output

One way to create a task is to learn from math. You can generate some random math statement or modify some theorems to get something new and build a new task from that.


For example, there is a statement called the “Goldbach’s conjecture”. It says: “each even number no less than four can be expressed as the sum of two primes”. Let’s modify it. How about a statement like that: “each integer no less than 12 can be expressed as the sum of two composite numbers.” Not like the Goldbach’s conjecture, I can prove this theorem.


You are given an integer n no less than 12, express it as a sum of two composite numbers.


Input

The only line contains an integer n (12 ≤ n ≤ 1e6).


Output

Output two composite integers x and y (1 < x, y < n) such that x + y = n. If there are multiple solutions, you can output any of them.


Examples

input

12

output

4 8

input

15

output

6 9

input

23

output

8 15

input

1000000

output

500000 500000


Note

In the first example, 12 = 4 + 8 and both 4, 8 are composite numbers. You can output "6 6" or "8 4" as well.


In the second example, 15 = 6 + 9. Note that you can’t output "1 14" because 1 is not a composite number.


本博客给出本题截图:

image.png

image.png

题意:输入一个大于等于12的数,把它拆成两个合数并输出

AC代码

#include <iostream>
using namespace std;
int main()
{
    int n;
    cin >> n;
    if (n % 2) cout << 9 << ' ' << n - 9;
    else cout << 4 << ' ' << n - 4;
    return 0;
}

总结

水题,不解释


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