Word

文章目录

一、Word

总结

一、Word

本题链接：Word

题目：

A. Word

time limit per test2 seconds

memory limit per test256 megabytes

inputstandard input

outputstandard output

Vasya is very upset that many people on the Net mix uppercase and lowercase letters in one word. That’s why he decided to invent an extension for his favorite browser that would change the letters’ register in every word so that it either only consisted of lowercase letters or, vice versa, only of uppercase ones. At that as little as possible letters should be changed in the word. For example, the word HoUse must be replaced with house, and the word ViP — with VIP. If a word contains an equal number of uppercase and lowercase letters, you should replace all the letters with lowercase ones. For example, maTRIx should be replaced by matrix. Your task is to use the given method on one given word.

Input

The first line contains a word s — it consists of uppercase and lowercase Latin letters and possesses the length from 1 to 100.

Output

Print the corrected word s. If the given word s has strictly more uppercase letters, make the word written in the uppercase register, otherwise - in the lowercase one.

Examples

input

HoUse

output

house

input

ViP

output

VIP

input

maTRIx

output

matrix

本博客给出本题截图：

题意：输入一个字符串，大写字母多就把字符串都变成大写，小写多或者一样多都变成小写

AC代码

#include <iostream>
#include <string>
using namespace std;
int main()
{
    string a;
    cin >> a;
    int cnt1 = 0, cnt2 = 0;
    for (int i = 0; i < a.size(); i ++ )
        if (a[i] >= 'A' && a[i] <= 'Z') cnt1 ++;
        else cnt2 ++;
    if (cnt1 > cnt2)
        for (int i = 0; i < a.size(); i ++ )
            if (a[i] >= 'a' && a[i] <= 'z')
                a[i] = a[i] - 'a' + 'A';
    if (cnt1 <= cnt2)
        for (int i = 0; i < a.size(); i ++ )
            if (a[i] >= 'A' && a[i] <= 'Z')
                a[i] = a[i] - 'A' + 'a';
    cout << a;
    return 0;
}

总结

水题，不解释