和前端交互全部使用JSON,如何将数据库查询结果转换成JSON格式
返回多条数据
示例
importjsonfromdjango.httpimportHttpResponsefromdjango.coreimportserializersdefdb_to_json(request): scripts=Scripts.objects.all()[0:1] json_data=serializers.serialize('json', scripts) returnHttpResponse(json_data, content_type="application/json")
返回结果
[{ "fields": { "script_content": "abc", "script_type": "1" }, "model": "home_application.scripts", "pk": "03a0a7cf-567a-11e9-8566-9828a60543bb"}]
功能实现了,但是我需要返回一个约定好的JSON格式,查询结果放在 data 中
{"message": 'success', "code": '0', "data": []}
代码如下:
importjsonfromdjango.httpimportHttpResponsefromdjango.coreimportserializersdefdb_to_json2(request): # 和前端约定的返回格式result= {"message": 'success', "code": '0', "data": []} scripts=Scripts.objects.all()[0:1] # 序列化为 Python 对象result["data"] =serializers.serialize('python', scripts) # 转换为 JSON 字符串并返回returnHttpResponse(json.dumps(result), content_type="application/json")
调用结果
{ "message": "success", "code": "0", "data": [{ "fields": { "script_content": "abc", "script_type": "1" }, "model": "home_application.scripts", "pk": "03a0a7cf-567a-11e9-8566-9828a60543bb" }] }
有点难受的是,每条数据对象包含 fields,model,pk三个对象,分别代表字段、模型、主键,我更想要一个只包含所有字段的字典对象。虽然也可以处理,但还是省点性能,交给前端解析吧。
返回单个对象
代码:
fromdjango.forms.modelsimportmodel_to_dictfromdjango.httpimportHttpResponseimportjsondefobj_json(request): pk=request.GET.get('script_id') script=Scripts.objects.get(pk=pk) # 转为字典类型script=model_to_dict(script) returnHttpResponse(json.dumps(script), content_type="application/json")
返回JSON:
{ "script_id": "1534d8f0-59ad-11e9-a310-9828a60543bb", "script_content": "3", "script_name": "3", "script_type": "1"}