题目链接：点击打开链接
题目大意：略。
解题思路：略。
AC 代码
SELECT customer_id FROM (SELECT customer_id, total FROM Customer, (SELECT COUNT(*) total FROM Product) p GROUP BY customer_id HAVING COUNT(DISTINCT product_key) = total) RS
题目链接：点击打开链接
题目大意：略。
解题思路：略。
AC 代码
SELECT customer_id FROM (SELECT customer_id, total FROM Customer, (SELECT COUNT(*) total FROM Product) p GROUP BY customer_id HAVING COUNT(DISTINCT product_key) = total) RS
