Python实现告警通知到微信,还免费？

import json
import datetime
import requests
CORP_ID = ""
SECRET = ""
class WeChatPub:
    s = requests.session()
    def __init__(self):
        self.token = self.get_token()
    def get_token(self):
        url = f"https://qyapi.weixin.qq.com/cgi-bin/gettoken?corpid={CORP_ID}&corpsecret={SECRET}"
        rep = self.s.get(url)
        if rep.status_code != 200:
            print("request failed.")
            return
        return json.loads(rep.content)['access_token']
    def send_msg(self, content):
        url = "https://qyapi.weixin.qq.com/cgi-bin/message/send?access_token=" + self.token
        header = {
            "Content-Type": "application/json"
        }
        form_data = {
            "touser": "@all",
            "toparty": " PartyID1 | PartyID2 ",
            "totag": " TagID1 | TagID2 ",
            "msgtype": "textcard",
            "agentid": 1000002,
            "textcard": {
                "title": "服务异常告警",
                "description": content,
                "url": "URL",
                "btntxt": "更多"
            },
            "safe": 0
        }
        rep = self.s.post(url, data=json.dumps(form_data).encode('utf-8'), headers=header)
        if rep.status_code != 200:
            print("request failed.")
            return
        return json.loads(rep.content)
wechat = WeChatPub()
now = datetime.datetime.now()
timenow = now.strftime('%Y%m%d %H:%M:%S')
wechat.send_msg(f"<div class=\"gray\">{timenow}</div> <div class=\"normal\">服务cpu超过80%</div><div class=\"highlight\">请尽快排查！</div>")