正文
难度中等
SQL架构
Table: Teams
+---------------+----------+ | Column Name | Type | +---------------+----------+ | team_id | int | | team_name | varchar | +---------------+----------+ 此表的主键是 team_id，表中的每一行都代表一支独立足球队。
Table: Matches
+---------------+---------+ | Column Name | Type | +---------------+---------+ | match_id | int | | host_team | int | | guest_team | int | | host_goals | int | | guest_goals | int | +---------------+---------+ 此表的主键是 match_id，表中的每一行都代表一场已结束的比赛，比赛的主客队分别由它们自己的 id 表示，他们的进球由 host_goals 和 guest_goals 分别表示。
积分规则如下：
赢一场得三分；
平一场得一分；
输一场不得分。
写出一条SQL语句以查询每个队的 team_id，team_name 和 num_points。结果根据 num_points 降序排序，如果有两队积分相同，那么这两队按 team_id 升序排序。
查询结果格式如下：
Teams table: +-----------+--------------+ | team_id | team_name | +-----------+--------------+ | 10 | Leetcode FC | | 20 | NewYork FC | | 30 | Atlanta FC | | 40 | Chicago FC | | 50 | Toronto FC | +-----------+--------------+ Matches table: +------------+--------------+---------------+-------------+--------------+ | match_id | host_team | guest_team | host_goals | guest_goals | +------------+--------------+---------------+-------------+--------------+ | 1 | 10 | 20 | 3 | 0 | | 2 | 30 | 10 | 2 | 2 | | 3 | 10 | 50 | 5 | 1 | | 4 | 20 | 30 | 1 | 0 | | 5 | 50 | 30 | 1 | 0 | +------------+--------------+---------------+-------------+--------------+ Result table: +------------+--------------+---------------+ | team_id | team_name | num_points | +------------+--------------+---------------+ | 10 | Leetcode FC | 7 | | 20 | NewYork FC | 3 | | 50 | Toronto FC | 3 | | 30 | Atlanta FC | 1 | | 40 | Chicago FC | 0 | +------------+--------------+---------------+
