Problem Description：

For products that are wrapped in small packings it is necessary that the sheet of paper containing the directions for use is folded until its size becomes small enough. We assume that a sheet of paper is rectangular and only folded along lines parallel to its initially shorter edge. The act of folding along such a line, however, can be performed in two directions: either the surface on the top of the sheet is brought together, or the surface on its bottom. In both cases the two parts of the rectangle that are separated by the folding line are laid together neatly and we ignore any differences in thickness of the resulting folded sheet.

After several such folding steps have been performed we may unfold the sheet again and take a look at its longer edge holding the sheet so that it appears as a one-dimensional curve, actually a concatenation of line segments. If we move along this curve in a fixed direction we can classify every place where the sheet was folded as either type A meaning a clockwise turn or type V meaning a counter-clockwise turn. Given such a sequence of classifications, produce a drawing of the longer edge of the sheet assuming 90 degree turns at equidistant places.

Input：

The input contains several test cases, each on a separate line. Each line contains a nonempty string of characters A and V describing the longer edge of the sheet. You may assume that the length of the string is less than 200. The input file terminates immediately after the last test case.

Output：

For each test case generate a PostScript drawing of the edge with commands placed on separate lines. Start every drawing at the coordinates (300, 420) with the command "300 420 moveto". The first turn occurs at (310, 420) using the command "310 420 lineto". Continue with clockwise or counter-clockwise turns according to the input string, using a sequence of "x y lineto" commands with the appropriate coordinates. The turning points are separated at a distance of 10 units. Do not forget the end point of the edge and finish each test case by the commands stroke and showpage.

You may display such drawings with the gv PostScript interpreter, optionally after a conversion using the ps2ps utility.

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Sample Input：

V

AVV

Sample Output：

300 420 moveto

310 420 lineto

310 430 lineto

stroke

showpage

300 420 moveto

310 420 lineto

310 410 lineto

320 410 lineto

320 420 lineto

stroke

showpage

解题思路：

题意就是说：有个人，它从点（300，420）出发，先向X轴正方向走一步（每一步是10），此时他面朝X轴正方向。然后开始按照输入的指令走，如果指令是V，这人就向他左手边走一步，如果指令是A，他就向右手边走一步；此人往哪个方向走了一步，他现在就面朝哪个方向；比如最初面朝X轴正方向，向左走了一步，那么显然，此人目前面朝Y轴正方向。（我在这里将1定义为x轴正方向，2定义为y轴正方向，3定义为x轴负方向，4定义为y轴负方向）

程序代码：

#include<iostream>
#include<cstdio>
#include<cstring>
using namespace std;
#define step 10
#define N 210
char  s[N];
int main()
{
  int sx=300,sy=420,x,y,dir;
  while(cin>>s)
  {
    x=sx;
    y=sy;
    printf("%d %d moveto\n",x,y);
    x+=step;
    dir=1;//第一步，向右走 
    printf("%d %d lineto\n",x,y);
    for(int i=0;i<strlen(s);i++)
    {
      switch(dir)
      {
        case 1://面朝x轴正方向 
        {
          if(s[i]=='V')//向左，转为y轴正方向 
          {
            y+=step;
            dir=2;
          }
          else//向右，转为y轴负方向 
          {
            y-=step;
            dir=4;
          }
          break;
        }
        case 2://面朝y轴正方向 
        {
          if(s[i]=='V')//向左，转为x轴负方向 
          {
            x-=step;
            dir=3; 
          }
          else//向右，转为x轴正方向 
          {
            x+=step;
            dir=1;
          }
          break;
        }
        case 3://面朝x轴负方向 
        {
          if(s[i]=='V')//向左，转为y轴负方向 
          {
            y-=step;
            dir=4;
          }
          else//向右，转为y轴正方向 
          {
            y+=step;
            dir=2;
          }
          break; 
        }
        case 4://面朝y轴负方向 
        {
          if(s[i]=='V')//向左，转为x轴正方向 
          {
            x+=step;
            dir=1;
          }
          else//向右，转为x轴负方向 
          {
            x-=step;
            dir=3;
          }
          break;
        }
      }
      printf("%d %d lineto\n",x,y);
    }
    printf("stroke\nshowpage\n");
  }
  return 0;
}