Algorithm
题目概述:
Given n points on a 2D plane, find the maximum number of points that lie on the same straight line.
代码:
import java.util.HashMap; import java.util.Map; class Point { int x; int y; Point() { x = 0; y = 0; } Point(int a, int b) { x = a; y = b; } } public class Solution { public int maxPoints(Point[] points) { int n = points.length; if(n < 2) return n; int ret = 0; for(int i = 0; i < n; i++) { // 分别统计与点i重合以及垂直的点的个数 int dup = 1, vtl = 0; Map<Float, Integer> map = new HashMap<>(); Point a = points[i]; for(int j = 0; j < n; j++) { if(i == j) continue; Point b = points[j]; if(a.x == b.x) { if(a.y == b.y) dup++; else vtl++; } else { float k = (float)(a.y - b.y) / (a.x - b.x); if(map.get(k) == null) map.put(k, 1); else map.put(k, map.get(k) + 1); } } int max = vtl; for(float k: map.keySet()) { max = Math.max(max, map.get(k)); } ret = Math.max(ret, max + dup); } return ret; } }