HDOJ 1076 An Easy Task（闰年计算）

Problem Description

Ignatius was born in a leap year, so he want to know when he could hold his birthday party. Can you tell him?

Given a positive integers Y which indicate the start year, and a positive integer N, your task is to tell the Nth leap year from year Y.

Note: if year Y is a leap year, then the 1st leap year is year Y.

Input

The input contains several test cases. The first line of the input is a single integer T which is the number of test cases. T test cases follow.

Each test case contains two positive integers Y and N(1<=N<=10000).

Output

For each test case, you should output the Nth leap year from year Y.

Sample Input

3

2005 25

1855 12

2004 10000

Sample Output

2108

1904

43236

Hint：

We call year Y a leap year only if (Y%4==0 && Y%100!=0) or Y%400==0.

题意就是：输入一个年份year和一个n，求这个year之后的第n个闰年，

如果year是闰年，则算第一个闰年。

直接暴力做，并没有超时。

import java.util.Scanner;
public class Main{
    public static void main(String[] args) {
        Scanner sc = new Scanner(System.in);
        int t = sc.nextInt();
        while(t-->0){
            int year = sc.nextInt();
            int n = sc.nextInt();
            int nyear = 0;
            if((year%4==0&&year%100!=0)|(year%400==0)){
                nyear=1;
            }//如果year是闰年，nyear就加一
            while(nyear<n){//当nyear小于n时，就循环
                year++;
                if((year%4==0&&year%100!=0)|(year%400==0)){
                    nyear++;
                }//year是闰年，nyear就加加
            }
            System.out.println(year);
        }
    }
}