HDOJ 2029 Palindromes _easy version(回文串)

简介: HDOJ 2029 Palindromes _easy version(回文串)

Problem Description

“回文串”是一个正读和反读都一样的字符串,比如“level”或者“noon”等等就是回文串。请写一个程序判断读入的字符串是否是“回文”。


Input

输入包含多个测试实例,输入数据的第一行是一个正整数n,表示测试实例的个数,后面紧跟着是n个字符串。


Output

如果一个字符串是回文串,则输出”yes”,否则输出”no”.


Sample Input

4

level

abcde

noon

haha


Sample Output

yes

no

yes

no


水过,水过~~

import java.util.Scanner;
public class Main {
    public static void main(String args[]){
        Scanner sc = new Scanner(System.in);
        int n = sc.nextInt();
        sc.next();
        while(n-->0){
            boolean isNo = false;
            String strs = sc.nextLine();
            for(int i=0;i<strs.length()/2;i++){
                if(strs.charAt(i) != strs.charAt(strs.length()-i-1)){
                    System.out.println("no");
                    isNo = true;
                    break;
                }
            }
            if(!isNo)
            System.out.println("yes");
        }
    }
}
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