3、从尾到头打印链表 (栈+list)
/** * public class ListNode { * int val; * ListNode next = null; * * ListNode(int val) { * this.val = val; * } * } * */ import java.util.Stack; import java.util.ArrayList; public class Solution { public ArrayList<Integer> printListFromTailToHead(ListNode listNode) { ArrayList<Integer> list=new ArrayList<Integer>(); if(listNode==null){ return list; } Stack<Integer> stack=new Stack<Integer>(); while(listNode!=null){ stack.push(listNode.val); listNode=listNode.next; } while(!stack.isEmpty()){ list.add(stack.pop()); } return list; } }
14 、链表的倒数第K个节点 (快慢指针+k<链表length校验)
import java.util.*; /* * public class ListNode { * int val; * ListNode next = null; * public ListNode(int val) { * this.val = val; * } * } */ public class Solution { /** * 代码中的类名、方法名、参数名已经指定,请勿修改,直接返回方法规定的值即可 * * * @param pHead ListNode类 * @param k int整型 * @return ListNode类 */ public ListNode FindKthToTail (ListNode pHead, int k) { // write code here if(pHead==null||k<0){ return pHead; } ListNode cur=pHead; ListNode begin=pHead; for(int i=0;i<k;i++){ ///判断链表长度是否小于k if(cur==null){ return null; }else{ cur=cur.next; } } while(cur!=null){ cur=cur.next; begin=begin.next; } return begin; } }
15 、反转链表 (头插法,双指针法)
//头插法
/* public class ListNode { int val; ListNode next = null; ListNode(int val) { this.val = val; } }*/ public class Solution { public ListNode ReverseList(ListNode head) { if(head==null){ return null; } ListNode newhead=new ListNode(-1); ListNode next=null; while(head!=null){ next=head.next; head.next=newhead.next; newhead.next=head; head=next; } return newhead.next; } }
//双指针法
/* public class ListNode { int val; ListNode next = null; ListNode(int val) { this.val = val; } }*/ public class Solution { public ListNode ReverseList(ListNode head) { if(head==null){ return null; } //判断边界条件 ListNode pre=null; ListNode cur=head; ListNode next=null; while(cur!=null){ next=cur.next; cur.next=pre; pre=cur; cur=next; } return pre; } }
16 、合并两个排序链表
/* public class ListNode { int val; ListNode next = null; ListNode(int val) { this.val = val; } }*/ public class Solution { public ListNode Merge(ListNode list1,ListNode list2) { if(list1==null){ return list2; }else if(list2==null){ return list1; } ListNode root=new ListNode(-1); ListNode head=root; while(list1!=null&&list2!=null){ if(list1.val>list2.val){ head.next=list2; head=list2; list2=list2.next; }else{ head.next=list1; head=list1; list1=list2.next; } } if(list1!=null){ head.next=list1; } if(list2!=null){ head.next=list2; } return root.next; } }