Java码农必须掌握的循环删除List元素的正确方法！

public static void main(String\[\] args) {
    List<String> list = new ArrayList<>(Arrays.asList("a1", "ab2", "a3", "ab4", "a5", "ab6", "a7", "ab8", "a9"));
    /**
     * 报错
     * java.util.ConcurrentModificationException
     */
    for (String str : list) {
        if (str.contains("b")) {
            list.remove(str);
        }
    }
    /**
     * 报错：下标越界
     * java.lang.IndexOutOfBoundsException
     */
    int size = list.size();
    for (int i = 0; i < size; i++) {
        String str = list.get(i);
        if (str.contains("b")) {
            list.remove(i);
        }
    }
    /**
     * 正常删除，每次调用size方法，损耗性能，不推荐
     */
    for (int i = 0; i < list.size(); i++) {
        String str = list.get(i);
        if (str.contains("b")) {
            list.remove(i);
        }
    }
    /**
     * **正常删除，推荐使用**
     */
    for (Iterator<String> ite = list.iterator(); ite.hasNext();) {
        String str = ite.next();
        if (str.contains("b")) {
            ite.remove();
        }
    }
    /**
     * 报错
     * java.util.ConcurrentModificationException
     */
    for (Iterator<String> ite = list.iterator(); ite.hasNext();) {
        String str = ite.next();
        if (str.contains("b")) {
            list.remove(str);
        }
    }
}