python编程：合并文本_利用列表或字典将两个通讯录文本合并

#利用字符串和列表将两个通讯录文本合并为一个文本
def main():
    ftele1=open('TeleAddressBook.txt','rb')
    ftele2=open('EmailAddressBook.txt','rb')
    ftele1.readline()#跳过第一行
    ftele2.readline()
    lines1 = ftele1.readlines()
    lines2 = ftele2.readlines()
    list1_name = []  
    list1_tele = []
    list2_name = []  
    list2_email = []
    for line in lines1:#获取第一个文本中的姓名和电话信息
        elements = line.split()
        list1_name.append(str(elements[0].decode('gbk')))
        list1_tele.append(str(elements[1].decode('gbk')))    #将文本读出来的bytes转换为str类型
    for line in lines2:#获取第二个文本中的姓名和邮件信息
        elements = line.split()
        list2_name.append(str(elements[0].decode('gbk')))
        list2_email.append(str(elements[1].decode('gbk')))
    ###开始处理###
    lines = []
    lines.append('姓名\t    电话   \t  邮箱\n')
    #按索引方式遍历姓名列表1
    for i in range(len(list1_name)): 
        s= ''
        if list1_name[i] in list2_name:
                j = list2_name.index(list1_name[i]) #找到姓名列表1对应列表2中的姓名索引位置
                s = '\t'.join([list1_name[i], list1_tele[i], list2_email[j]])
                s += '\n'
        else:
                s = '\t'.join([list1_name[i], list1_tele[i], str('   -----   ')])
                s += '\n'
        lines.append(s)
    #处理姓名列表2中剩余的姓名        
    for i in range(len(list2_name)): 
        s= ''
        if list2_name[i] not in list1_name:
                s = '\t'.join([list2_name[i], str('   -----   '), list2_email[i]])
                s += '\n'
        lines.append(s)  
    ftele3 = open('AddressBook.txt', 'w')
    ftele3.writelines(lines)
    ftele3.close()
    ftele1.close()
    ftele2.close()
    print("The addressBooks are merged!")
if __name__ == "__main__":
    main()

#利用字典将两个通讯录文本合并为一个文本
def main():
        ftele2=open('TeleAddressBook.txt','rb')
        ftele1=open('EmailAddressBook.txt','rb')
        ftele1.readline()#跳过第一行
        ftele2.readline()
        lines1 = ftele1.readlines()
        lines2 = ftele2.readlines()
        dic1 = {}   #字典方式保存
        dic2 = {}
        for line in lines1:#获取第一个本文中的姓名和电话信息
                elements = line.split()
                #将文本读出来的bytes转换为str类型
                dic1[elements[0]] = str(elements[1].decode('gbk'))
        for line in lines2:#获取第二个本文中的姓名和电话信息
                elements = line.split()
                dic2[elements[0]] = str(elements[1].decode('gbk'))
        ###开始处理###
        lines = []
        lines.append('姓名\t    电话   \t  邮箱\n')
        for key in dic1:
            s= ''
            if key in dic2.keys():
                    s = '\t'.join([str(key.decode('gbk')), dic1[key], dic2[key]])
                    s += '\n'
            else:
                    s = '\t'.join([str(key.decode('gbk')), dic1[key], str('   -----   ')])
                    s += '\n'
            lines.append(s)
        for key in dic2:
            s= ''
            if key not in dic1.keys():
                    s = '\t'.join([str(key.decode('gbk')), str('   -----   '), dic2[key]])
                    s += '\n'       
            lines.append(s)
        ftele3 = open('AddressBook.txt', 'w')
        ftele3.writelines(lines)
        ftele3.close()
        ftele1.close()
        ftele2.close()
        print("The addressBooks are merged!")
if __name__ == "__main__":
        main()