java中为什么重写equals时必须重写hashCode方法？

/**
     * Returns a hash code value for the object. This method is
     * supported for the benefit of hash tables such as those provided by
     * {@link java.util.HashMap}.
     * <p>
     * The general contract of {@code hashCode} is:
     * <ul>
     * <li>Whenever it is invoked on the same object more than once during
     *     an execution of a Java application, the {@code hashCode} method
     *     must consistently return the same integer, provided no information
     *     used in {@code equals} comparisons on the object is modified.
     *     This integer need not remain consistent from one execution of an
     *     application to another execution of the same application.
     * <li>If two objects are equal according to the {@code equals(Object)}
     *     method, then calling the {@code hashCode} method on each of
     *     the two objects must produce the same integer result.
     * <li>It is <em>not</em> required that if two objects are unequal
     *     according to the {@link java.lang.Object#equals(java.lang.Object)}
     *     method, then calling the {@code hashCode} method on each of the
     *     two objects must produce distinct integer results.  However, the
     *     programmer should be aware that producing distinct integer results
     *     for unequal objects may improve the performance of hash tables.
     * </ul>
     * <p>
     * As much as is reasonably practical, the hashCode method defined by
     * class {@code Object} does return distinct integers for distinct
     * objects. (This is typically implemented by converting the internal
     * address of the object into an integer, but this implementation
     * technique is not required by the
     * Java&trade; programming language.)
     *
     * @return  a hash code value for this object.
     * @see     java.lang.Object#equals(java.lang.Object)
     * @see     java.lang.System#identityHashCode
     */
    public native int hashCode();

/**
     * Indicates whether some other object is "equal to" this one.
     * <p>
     * The {@code equals} method implements an equivalence relation
     * on non-null object references:
     * <ul>
     * <li>It is <i>reflexive</i>: for any non-null reference value
     *     {@code x}, {@code x.equals(x)} should return
     *     {@code true}.
     * <li>It is <i>symmetric</i>: for any non-null reference values
     *     {@code x} and {@code y}, {@code x.equals(y)}
     *     should return {@code true} if and only if
     *     {@code y.equals(x)} returns {@code true}.
     * <li>It is <i>transitive</i>: for any non-null reference values
     *     {@code x}, {@code y}, and {@code z}, if
     *     {@code x.equals(y)} returns {@code true} and
     *     {@code y.equals(z)} returns {@code true}, then
     *     {@code x.equals(z)} should return {@code true}.
     * <li>It is <i>consistent</i>: for any non-null reference values
     *     {@code x} and {@code y}, multiple invocations of
     *     {@code x.equals(y)} consistently return {@code true}
     *     or consistently return {@code false}, provided no
     *     information used in {@code equals} comparisons on the
     *     objects is modified.
     * <li>For any non-null reference value {@code x},
     *     {@code x.equals(null)} should return {@code false}.
     * </ul>
     * <p>
     * The {@code equals} method for class {@code Object} implements
     * the most discriminating possible equivalence relation on objects;
     * that is, for any non-null reference values {@code x} and
     * {@code y}, this method returns {@code true} if and only
     * if {@code x} and {@code y} refer to the same object
     * ({@code x == y} has the value {@code true}).
     * <p>
     * Note that it is generally necessary to override the {@code hashCode}
     * method whenever this method is overridden, so as to maintain the
     * general contract for the {@code hashCode} method, which states
     * that equal objects must have equal hash codes.
     *
     * @param   obj   the reference object with which to compare.
     * @return  {@code true} if this object is the same as the obj
     *          argument; {@code false} otherwise.
     * @see     #hashCode()
     * @see     java.util.HashMap
     */
    public boolean equals(Object obj) {
        return (this == obj);
    }

1.在 Java 应用程序执行期间，在对同一对象多次调用 hashCode 方法时，必须一致地返回相同的整数，前提是将对象进行 equals 比较时所用的信息没有被修改。
　从某一应用程序的一次执行到同一应用程序的另一次执行，该整数无需保持一致。    
2.如果根据 equals(Object) 方法，两个对象是相等的，那么对这两个对象中的每个对象调用 hashCode 方法都必须生成相同的整数结果。    
3.如果根据 equals(java.lang.Object) 方法，两个对象不相等，那么两个对象不一定必须产生不同的整数结果。
　但是，程序员应该意识到，为不相等的对象生成不同整数结果可以提高哈希表的性能。

/**
     * @see Person
     * @param args
     */
    public static void main(String[] args)
    {
        HashMap<Person, Integer> map = new HashMap<Person, Integer>();

        Person p = new Person("jack",22,"男");
        Person p1 = new Person("jack",22,"男");

        System.out.println("p的hashCode:"+p.hashCode());
        System.out.println("p1的hashCode:"+p1.hashCode());
        System.out.println(p.equals(p1));
        System.out.println(p == p1);

        map.put(p,888);
        map.put(p1,888);
        map.forEach((key,val)->{
            System.out.println(key);
            System.out.println(val);
        });
    }

public class Person
{
    private String name;

    private int age;

    private String sex;

    Person(String name,int age,String sex){
        this.name = name;
        this.age = age;
        this.sex = sex;
    }
}

p的hashCode:356573597
p1的hashCode:1735600054
false
false
com.blueskyli.练习.Person@677327b6
888
com.blueskyli.练习.Person@1540e19d
888

public class Person
{
    private String name;

    private int age;

    private String sex;

    Person(String name,int age,String sex){
        this.name = name;
        this.age = age;
        this.sex = sex;
    }

    @Override public boolean equals(Object obj)
    {
        if(obj instanceof Person){
            Person person = (Person)obj;
            return name.equals(person.name);
        }
        return super.equals(obj);
    }
}

p的hashCode:356573597
p1的hashCode:1735600054
true
false
com.blueskyli.练习.Person@677327b6
888
com.blueskyli.练习.Person@1540e19d
888

public class Person
{
    private String name;

    private int age;

    private String sex;

    Person(String name,int age,String sex){
        this.name = name;
        this.age = age;
        this.sex = sex;
    }

    @Override public boolean equals(Object obj)
    {
        if(obj instanceof Person){
            Person person = (Person)obj;
            return name.equals(person.name);
        }
        return super.equals(obj);
    }

    @Override public int hashCode()
    {
        return name.hashCode();
    }
}

p的hashCode:3254239
p1的hashCode:3254239
true
false
com.blueskyli.练习.Person@31a7df
888