1074. Reversing Linked List (25)

#include <iostream>
#include <vector>
#include <algorithm>
using namespace std;

struct node {
    int address, data, next;
};

const int NUM = 100001;
node nodes[NUM];
vector<node> list;

int main(){
    int fnAdress, n, k;
    cin >> fnAdress >> n >> k;

    for (int i = 0; i < n; i++) {
        node nodet;
        cin >> nodet.address >> nodet.data >> nodet.next;
        nodes[nodet.address] = nodet;//将每一个node放入正确的位置
    }

    int address = fnAdress;
    while (address != -1) {//去噪
        list.push_back(nodes[address]);
        address = nodes[address].next;
    }

    int size = (int)list.size();
    int round = size / k;
    for (int i = 0; i < round; i++) {
        int start = i * k;
        int end = (i + 1) * k;
        reverse(list.begin() + start, list.begin() + end);
    }
    for(int i = 0; i < size - 1; i++){
        printf("%05d %d %05d\n", list[i].address, list[i].data, list[i+1].address);
    }

    printf("%05d %d %d\n", list[size - 1].address, list[size - 1].data, -1);

    return 0;
}