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public
class
编程求出下式中n的最大值 {
/**
* @param args
*/
public
static
void
main(String[] args) {
// TODO Auto-generated method stub
int
num =
0
, sum =
0
;
System.out.println(
"编程求出下式中n的最大值"
+
"+"
+
" 2*2+4*4+6*6+……+n*n<1500。"
);
while
(sum <
1500
) {
num +=
2
;
sum += num * num;
}
System.out.println(
"N的最大值:"
+ (num -
2
));
}
}
|
本文转自 Y幕徐 51CTO博客,原文链接:http://blog.51cto.com/765133133/1419466