一 问题
自己开发的程序,如何用shell 脚本实现 启动,关闭,重启,查看状态?
二 方案
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|
#!/bin/sh
SERVICE=
"my_service"
start(){
echo
"starting..."
nohup
$SERVICE > $SERVICE.log 2>&1 &
if
[ $? -
ne
0 ]
then
echo
"start failed, please check the log!"
exit
$?
else
echo
$! > $SERVICE.pid
echo
"start success"
fi
}
stop(){
echo
"stopping..."
kill
-9 `
cat
$SERVICE.pid`
if
[ $? -
ne
0 ]
then
echo
"stop failed, may be $SERVICE isn't running"
exit
$?
else
rm
-rf $SERVICE.pid
echo
"stop success"
fi
}
restart(){
stop&&start
}
status(){
num=`
ps
-ef |
grep
$SERVICE |
grep
-
v
grep
|
wc
-l`
if
[ $num -
eq
0 ]
then
echo
"$SERVICE isn't running"
else
echo
"$SERVICE is running"
fi
}
case
$1
in
start) start ;;
stop) stop ;;
restart) restart ;;
status) status ;;
*)
echo
"Usage: $0 {start|stop|restart|status}"
;;
esac
exit
0
|
本文转自 boy461205160 51CTO博客,原文链接:http://blog.51cto.com/461205160/1740578