Python实现二叉树的遍历
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class BinaryTree( object ):
def __init__( self , value = None , left = None , right = None ):
self .value = value
self .left = left
self .right = right
def rebuild( self , preOrder, inOrder):
"""
根据前序列表和中序列表,重建二叉树
:param preOrder: 前序列表
:param inOrder: 中序列表
:return: 二叉树
"""
if preOrder = = None or inOrder = = None or len (preOrder) < = 0 or len (inOrder) < = 0 \
or len (preOrder) ! = len (inOrder):
return None
cur = BinaryTree(preOrder[ 0 ])
index = inOrder.index(preOrder[ 0 ])
cur.left = self .rebuild(preOrder[ 1 : index + 1 ], inOrder[:index])
cur.right = self .rebuild(preOrder[index + 1 :], inOrder[index + 1 :])
return cur
def preOrder( self , tree):
"""
前序遍历
:param tree:
:return:
"""
if tree = = None :
return None
print (tree.value, end = ' ' )
self .preOrder(tree.left)
self .preOrder(tree.right)
def preOrderLoop( self , tree):
"""
前序遍历的循环实现
:param tree:
:return:
"""
if tree = = None :
return None
lst = []
node = tree
while node ! = None or len (lst) > 0 :
if node ! = None :
lst.append(node)
print (node.value, end = ' ' )
node = node.left
else :
item = lst[ len (lst) - 1 ]
lst = lst[: - 1 ]
node = item.right
def inOrder( self , tree):
"""
中序遍历
:param tree:
:return:
"""
if tree = = None :
return None
self .inOrder(tree.left)
print (tree.value, end = ' ' )
self .inOrder(tree.right)
def inOrderLoop( self , tree):
"""
中序遍历循环实现
:param tree:
:return:
"""
if tree = = None :
return
lst = []
node = tree
while node ! = None or len (lst) > 0 :
if node ! = None :
lst.append(node)
node = node.left
else :
item = lst[ len (lst) - 1 ]
lst = lst[: - 1 ]
print (item.value, end = ' ' )
node = item.right
def postOrder( self , tree):
"""
后序遍历
:param tree:
:return:
"""
if tree = = None :
return None
self .postOrder(tree.left)
self .postOrder(tree.right)
print (tree.value, end = ' ' )
def postOrderLoop( self , tree):
"""
后续遍历的循环实现
:param tree:
:return:
"""
if tree = = None :
return None
visited = set ()
lst = []
node = tree
while node ! = None or len (lst) > 0 :
if node ! = None :
lst.append(node)
node = node.left
else :
item = lst[ len (lst) - 1 ]
if item.right ! = None and item.right not in visited:
node = item.right
else :
print (item.value, end = ' ' )
visited.add(item)
lst = lst[: - 1 ]
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