需求：假设让用户输入两次数字，第一次为12，第二次为34，实现的组合为13，14，23，24；
即第一次输入的每一个数字与第2次输入的每一个数字进行俩俩组合。
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num1
=
input
(
'请输入0-9之间任意一个或多个数字：'
)
num2
=
input
(
'请再次输入0-9之间任意一个或多个数字：'
)
def
account(num1,num2):
print
(
"两次输入数字的组合即将开始"
)
list1
=
[(x,y)
for
x
in
num1
for
y
in
num2 ]
num3
=
[]
for
list2
in
list1:
print
(''.join([
str
(x)
for
x
in
list2]))
num3.append(''.join([
str
(x)
for
x
in
list2]))
print
(
"组合完成，共有"
+
str
(
len
(num3))
+
"对组合！"
)
account(num1,num2)
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方法二，利用tkinter实现可视化按钮操作
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from
tkinter
import
*
root
=
Tk()
root.title(
"数字组合工具"
)
Label(root,text
=
"数字1"
).grid(row
=
0
,column
=
0
)
Label(root,text
=
"数字2"
).grid(row
=
1
,column
=
0
)
e1
=
Entry(root)
e2
=
Entry(root)
e1.grid(row
=
0
,column
=
1
,padx
=
5
,pady
=
5
)
e2.grid(row
=
1
,column
=
1
,padx
=
5
,pady
=
5
)
def
account():
num1
=
str
(e1.get())
num2
=
str
(e2.get())
print
(
"两次输入数字的组合即将开始"
)
list1
=
[(x,y)
for
x
in
num1
for
y
in
num2 ]
num3
=
[]
for
list2
in
list1:
print
(''.join([
str
(x)
for
x
in
list2]))
num3.append(''.join([
str
(x)
for
x
in
list2]))
print
(
"组合完成，共有"
+
str
(
len
(num3))
+
"对组合！"
)
Button(root,text
=
"进行组合"
,width
=
10
,command
=
account).grid(row
=
3
,column
=
0
,sticky
=
W,padx
=
10
,pady
=
5
)
Button(root,text
=
"退出"
,width
=
10
,command
=
root.quit).grid(row
=
3
,column
=
1
,sticky
=
E,padx
=
10
,pady
=
5
)
root.geometry(
"300x100+200+20"
)
mainloop()
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本文转自激情燃烧的岁月博客51CTO博客，原文链接http://blog.51cto.com/liuzhengwei521/1925499如需转载请自行联系原作者
weilovepan520
