1、转换字符串的输入格式为：原来字符串里的字符＋该字符连续出现的个数，例如字符串：1233422222，转化为1121324125。
我们用sprintf来实现，类同printf。
#include "iostream"
#include "string"
using namespace std;
int main()
{
cout << "Enter the numbers: " << endl;
string str;
cin >> str;
size_t ilength = str.length();
int icount = 1;
char cMyChar[50];
cMyChar[0] = '\0';
int k;
for (k = 0; k < ilength - 1; k++)
{
if (str[k] == str[k + 1]) //预判断
{
icount++; //记录字符个数
}
else
{
sprintf(cMyChar + strlen(cMyChar), "%c%d", str[k], icount);
icount = 1;
}
}
if (str[k] == str[k - 1])
;
else
icount = 1;
sprintf(cMyChar + strlen(cMyChar), "%c%d", str[k], icount);
cout << cMyChar << endl;
return 1;
}
2、整数转换成字符串
#include "iostream"
using namespace std;
int main()
{
int iMyData;
cin >> iMyData;
char cToTransfer[56];
char cTemp[56];
int icount = 0; //标记位数
while(iMyData)
{
cTemp[icount++] = iMyData % 10 + '0';
iMyData = iMyData / 10;
}
cTemp[icount] = '\0';
cout << cTemp << endl;
icount--;
int j = icount, i = 0;
while(j >=0)
{
cToTransfer[i++] = cTemp[j--];
}
cToTransfer[i] = 0;
cout << cToTransfer << endl;
return 1;
}
3、字符串转换成整数
#include "iostream"
using namespace std;
int main()
{
char iMyData[56];
cin >> iMyData;
int iToTransfer[56];
int cTemp[56];
int icount = 0; //标记位数
int iSum = 0;
while(iMyData[icount])
{
iSum = iSum * 10 + iMyData[icount] - '0';
icount++;
}
cout << iSum << endl;
return 1;
}
