一，第一种：
采用文件中contact.txt中第一行读出后，将其分割成列表，然后对其判断，但是不支持部门查询。
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#!/usr/bin/env python
while
True:
name=raw_input(
'please input name:'
)
if
name ==
'small'
:
while
True:
password=raw_input(
'please input password:'
)
if
password ==
'123'
:
print
'welcome login system'
while
True:
input=raw_input(
'please input employee name:'
)
f=open(
'contact.txt'
,
'r'
)
match=
0
for
i
in
f.readlines():
if
input == i.split(
" "
)[
1
]:
print i
match=
1
if
match==
0
:
print
"user not found,please input"
f.close()
#
break
else
:
print
'password is wrong,try again'
break
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第二种：将文件中每行读出后成字符串的形式，因此支持各个字段查询。
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#!/usr/bin/python
while
True:
input = raw_input(
"please input your username:"
)
if
input ==
'small'
:
password = raw_input(
"please input your pass:"
)
p =
'123'
while
password != p:
password = raw_input(
"wrong passwd,input again:"
)
else
:
print
"welcome login to linux!"
while
True:
match_yes =
0
input = raw_input(
"\033[32mPlease input name whom you want to search:\33[0m"
)
contact_file = file(
'contact_list.txt'
,
'r'
)
while
True:
line = contact_file.readline()
if
len(line) ==
0
:
break
if
input !=
""
and input
in
line:
print
"match item: \33{36,1m%s\033[0m"
% line
match_yes =
1
if
match_yes ==
0
:print
"no match item found"
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第三种：用字典的方式来实现
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#!/usr/bin/env python
f=file(
'contact.txt'
)
personal={}
for
line
in
f.readlines():
name= line.split()[
0
]
personal[name]=line
while
True:
f=file(
'contact.txt'
)
personal={}
for
line
in
f.readlines():
name= line.split()[
0
]
personal[name]=line
while
True:
input=raw_input(
'please input username:'
).strip()
if
len(input) ==
0
:
continue
if
input
in
personal:
#
if
personal.has_key(input):
#print
'username information: %s'
%personal.
get
(input)
print
'username information: %s'
%personal[input]
else
:
print
'%s not found,please input'
%input
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本文转自 deng304749970 51CTO博客，原文链接：http://blog.51cto.com/damondeng/1354239，如需转载请自行联系原作者
