165. Compare Version Numbers
Compare two version numbers version1 and version2.
If version1 > version2 return 1, if version1 < version2 return -1, otherwise return 0.
You may assume that the version strings are non-empty and contain only digits and the . character.
The . character does not represent a decimal point and is used to separate number sequences.
For instance, 2.5 is not "two and a half" or "half way to version three", it is the fifth second-level revision of the second first-level revision.
Here is an example of version numbers ordering:
0.1 < 1.1 < 1.2 < 13.37
思路：
1.将两个版本字符串都分割好存入vector中。
2.比较2个vector中元素的大小。
其中注意：1 == 1.0.0
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class
Solution {
public
:
vector<
int
> stringSplit(string s,
const
char
* split)
{
vector<
int
> result;
const
int
sLen = s.length();
char
*cs =
new
char
[sLen + 1];
strcpy
(cs, s.data());
char
*p;
char
* end;
p =
strtok
(cs, split);
while
(p)
{
printf
(
"%s\n"
, p);
string tmp(p);
int
v =
static_cast
<
int
>(
strtol
(tmp.c_str(),&end,10));
result.push_back(v);
p =
strtok
(NULL, split);
}
return
result;
}
int
compareVersion(string version1, string version2) {
vector<
int
> vecInt1 = stringSplit(version1,
"."
);
vector<
int
> vecInt2 = stringSplit(version2,
"."
);
int
i;
for
(i = 0; i < min(vecInt1.size(),vecInt2.size()); i++)
{
if
(vecInt1[i] < vecInt2[i])
return
-1;
else
if
(vecInt1[i] > vecInt2[i])
return
1;
}
if
( vecInt1.size() < vecInt2.size())
{
int
j = i;
for
(;j <vecInt2.size();j++)
{
if
(vecInt2[j] > 0)
return
-1;
}
return
0;
}
else
if
(vecInt1.size() > vecInt2.size())
{
int
j = i;
for
(;j < vecInt1.size();j++)
{
if
(vecInt1[j] > 0)
return
1;
}
return
0;
}
else
return
0;
}
};
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本文转自313119992 51CTO博客，原文链接:http://blog.51cto.com/qiaopeng688/1836522
