JAVA异步调用

就是A调用一个系统的工作流，系统工作流做完反馈B，这是一个异步的过程。现在想做成同步的，就是A启动工作流之后停止，一直等待B被回调了，设定超时时间，如果超时A返回错误；否则返回成功。

public class AClient2C2 {

	private final long timeout = 10000;

	public void test(String taskId) {
		long count = 0;
		while (BService2C2.getInstance().isHasTask(taskId) && count < timeout) {

			try {
				System.out.println("wait+"+count);
				Thread.sleep(1000);
				count += 1000;
			} catch (InterruptedException e) {
				// TODO Auto-generated catch block
				e.printStackTrace();
			}
		}
		if(count>=timeout) {
			System.out.println("超时");
		}

	}
	
	public static void main(String[] args){
		
		BService2C2.getInstance().regesitTaskId("aaaa");
		AClient2C2 ac = new AClient2C2();
		ac.test("aaaa");
		BService2C2.getInstance().removeTaskId("aaaa");
	}
}

import java.util.HashMap;
import java.util.Map;


public class BService2C2 {
	
	
	private static BService2C2 instance;
	
	private static Map<String,String> map = new HashMap<String,String>();
	
    private BService2C2() {
    	
    }
    
    public static BService2C2 getInstance(){
    	if(instance==null){
    		instance = new BService2C2();
    	}
    	return instance;
    }
    
    
    public void regesitTaskId(String taskId){
    	map.put(taskId, taskId);
    }
    
    public void removeTaskId(String taskId){
    	map.remove(taskId);
    }
    
    public boolean isHasTask(String taskId){
    	if(null!=map.get(taskId)){
    		return Boolean.TRUE;
    	}
    	return Boolean.FALSE;
    }
    
}