一个关于判断文件夹或文件名是否有空格的小脚本，没啥大作用，自己练习瞎写的。
不过涉及到的知识点还挺多。
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cat
check_filename.py
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#!/usr/bin/python
import
os, sys
res_dir
=
os.listdir(
"/var/www/html"
)
for
res_list
in
range
(
len
(res_dir)):
print
res_list,
"."
,res_dir[res_list]
dir_num
=
raw_input
(
"Please Input project number:"
)
def
func(x):
try
:
x
=
int
(x)
return
isinstance
(x,
int
)
except
ValueError:
print
"input type is error!!!"
sys.exit()
func(dir_num)
if
int
(dir_num) >
=
len
(res_dir)
or
int
(dir_num) <
0
:
print
"input number is error!!!"
sys.exit()
dir_path
=
"/var/www/html/"
+
res_dir[
int
(dir_num)]
file_name_list
=
[]
file_path_list
=
[]
for
root, dirs, files
in
os.walk(dir_path):
for
file_list
in
files:
if
" "
in
file_list:
file_name_list.append(os.path.join(root,file_list))
for
dir_list
in
dirs:
if
" "
in
dir_list:
file_path_list.append(os.path.join(root,dir_list))
if
len
(file_name_list)
=
=
0
:
pass
else
:
print
"Warning: These files has a problem!!!"
for
filelists
in
file_name_list:
print
filelists
if
len
(file_path_list)
=
=
0
:
pass
else
:
print
"\nWarning: These directorys has a problem!!!"
for
dislists
in
file_path_list:
print
dislists
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本文转自 cyr520 51CTO博客，原文链接:http://blog.51cto.com/cyr520/1281639
