这是博问中的一个问题:http://q.cnblogs.com/q/39172/
我的方案如下:
function isOverlap(idOne,idTwo){ var objOne=$("#"+idOne), objTwo=$("#"+idTwo), offsetOne = objOne.offset(), offsetTwo = objTwo.offset(), topOne=offsetOne.top, topTwo=offsetTwo.top, leftOne=offsetOne.left, leftTwo=offsetTwo.left, widthOne = objOne.width(), widthTwo = objTwo.width(), heightOne = objOne.height(), heightTwo = objTwo.height(); var leftTop = leftTwo > leftOne && leftTwo < leftOne+widthOne && topTwo > topOne && topTwo < topOne+heightOne, rightTop = leftTwo+widthTwo > leftOne && leftTwo+widthTwo < leftOne+widthOne && topTwo > topOne && topTwo < topOne+heightOne, leftBottom = leftTwo > leftOne && leftTwo < leftOne+widthOne && topTwo+heightTwo > topOne && topTwo+heightTwo < topOne+heightOne, rightBottom = leftTwo+widthTwo > leftOne && leftTwo+widthTwo < leftOne+widthOne && topTwo+heightTwo > topOne && topTwo+heightTwo < topOne+heightOne; return leftTop || rightTop || leftBottom || rightBottom; }
原理很简单,就是判断一个元素的四个点是否在另一个元素内部。
Demo:
如果有其他方案欢迎提出。