(
@booker varchar ( 100 )
)
AS
declare @str varchar ( 1000 )
set @str = ' select * from tb_itregister where booker in( ' + @booker + ' ) '
execute ( @str )
调用：
string booker = "a,b";
booker = booker. Replace (",", " ' , ' ");
booker = " ' " + booker + " ' ";
/************************************************************
问题描述： id值可能有数千个之多，怎么提高效率？
例子：select * from table1 where id in (1,3,6,10,...,8000) and type = 1
************************************************************/
--例如:
SELECT *
FROM tb
WHERE id IN (1, 2, 3, 4, ........)
AND NAME = 'best'
--1.将括号的条件做成变量
DECLARE @str VARCHAR(4000)
SET @str = '1,2,3,4,5.......'
--2.然后将@s拆分后插入临时表
CREATE TABLE #t
(
id VARCHAR(10)
)
DECLARE @i INT
DECLARE @len INT
SET @i = 1
WHILE @i < LEN(@str + ',')
BEGIN
INSERT #t
SELECT SUBSTRING(@str + ',', @i, CHARINDEX(',', @str + ',', @i) -@i)
SET @i = CHARINDEX(',', @str + ',', @i) + 1
END
--3利用临时表和原表进行连接取值
SELECT k.*
FROM tb k
INNER JOIN #t p
ON p.id = k.id
WHERE NAME = 'best'
本文转自曾祥展博客园博客，原文链接：http://www.cnblogs.com/zengxiangzhan/archive/2010/01/03/1638152.html，如需转载请自行联系原作者
