用途：方便js操作查询json数据。
下载网址：http://jslinq.codeplex.com/
使用方法：只需要引用linq.js即可。
查询方法：
一、where查询
|
1
2
3
4
5
6
7
8
|
var
myList = [
{ Name:
"Jim"
, Age: 20 },
{ Name:
"Kate"
, Age: 21 },
{ Name:
"Lilei"
, Age: 18 },
{ Name:
"John"
, Age: 14 },
{ Name:
"LinTao"
, Age: 25 }
];
var
arrRes = Enumerable.From(myList).Where(
"x=>x.Name=='Jim'"
).ToArray();
|
二、排序：OrderBy
|
1
2
3
4
5
6
7
8
|
var
myList = [
{ Name:
"Jim"
, Age: 20 },
{ Name:
"Kate"
, Age: 21 },
{ Name:
"Lilei"
, Age: 18 },
{ Name:
"John"
, Age: 14 },
{ Name:
"LinTao"
, Age: 25 }
];
var
arrRes = Enumerable.From(myList).OrderBy(
"x=>x.Age"
).ToArray();
//降序OrderByDescending()
|
三、去重：Distinct
|
1
2
3
4
5
6
7
8
|
var
myList = [
{ Name:
"Jim"
, Age: 20 },
{ Name:
"Kate"
, Age: 20 },
{ Name:
"Lilei"
, Age: 20 },
{ Name:
"John"
, Age: 14 },
{ Name:
"LinTao"
, Age: 25 }
];
var
arrRes = Enumerable.From(myList).Distinct(
"x=>x.Age"
).ToArray();
|
四、遍历：ForEach
|
1
2
3
4
5
6
7
8
9
10
|
var
myList = [
{ Name:
"Jim"
, Age: 20 },
{ Name:
"Kate"
, Age: 20 },
{ Name:
"Lilei"
, Age: 20 },
{ Name:
"John"
, Age: 14 },
{ Name:
"LinTao"
, Age: 25 }
];
Enumerable.From(myList).ForEach(
function
(value, index){
document.write(
"值="
+value+
",索引="
+index);
});
|
五、取唯一对象：First、FirstOrDefault、Last、LastOrDefault、Single、SingleOrDefault
|
1
2
3
4
5
6
7
8
|
var
myList = [
{ Name:
"Jim"
, Age: 20 },
{ Name:
"Kate"
, Age: 20 },
{ Name:
"Lilei"
, Age: 20 },
{ Name:
"John"
, Age: 14 },
{ Name:
"LinTao"
, Age: 25 }
];
var
arrRes = Enumerable.From(myList).FirstOrDefault(
"x=>x.Age>18"
);
|
六、Skip、Take
|
1
2
|
Enumerable.Range(1,10).Skip(5)
//结果[6,7,8,9,10]
Enumerable.Range(1,10).Take(5)
//结果[1,2,3,4,5]
|
本文转自王磊的博客博客园博客，原文链接：http://www.cnblogs.com/vipstone/p/5588020.html，如需转载请自行联系原作者
