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行列转换实例
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表ttt有三个字段
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seq
--
序列
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jcxm
--
检查项目
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zhi
--
值
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数据分别如下:
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seq jcxm zhi
--
----- -------- --------
11
1
0.50
11
2
0.21
11
3
0.25
12
1
0.24
12
2
0.30
12
3
0.22
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实现功能
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创建视图时移动行值为列值
create
view v_view1
as
select seq,
sum(decode(jcxm,
1, zhi)) 检测项目1,
sum(decode(jcxm,
2, zhi)) 检测项目2,
sum(decode(jcxm,
3, zhi)) 检测项目3
from ttt
group
by seq;
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序号 检测项目1 检测项目2 检测项目3
11
0.50
0.21
0.25
12
0.24
0.30
0.22
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技巧:
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用THEN中的0和1来进行统计(
SUM)
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jcxm zhi
--
-- ----
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a
1
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b
1
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a
3
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d
2
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e
4
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f
5
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a
5
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d
3
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d
6
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b
5
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c
4
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b
3
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求他的zhi既是1,也是3,也是5的jcxm
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方法一
select jcxm
from ttt
group
by jcxm
having
sum(decode(zhi,
1,
-
1,
3,
-
1,
5,
-
1,
0))
=
-
3
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方法二
select jcxm
from ttt
group
by jcxm
having (
sign(
sum(decode(zhi,
1,
-
1,
0)))
+
sign(
sum(decode(zhi,
3,
-
1,
0)))
+
sign(
sum(decode(zhi,
5,
-
1,
0)))
<=-
3);
--
--------
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a
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b
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说明:
sign()函数根据某个值是0、正数还是负数,分别返回0、
1、
-
1
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所以可以用sign和decode来完成比较字段大小来区某个字段
select decode(
sign(字段1
-字段2),
-
1,字段3,字段4)
from dual;
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sign是一个对于写分析SQL有很强大的功能
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下面我对sign进行一些总结:
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但属性student取0和1以外的值,或者student取两个以上的标法值,问题就不会这么简单了
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解决办法就是特征函数(
abs(),
sign())
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常用的特征算法
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[A=B]=
1-
abs(
sign(A-B))
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[A!=B]=
abs(
sign(A-B))
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[A
<B]=
1-
sign(
1+
sign(A-B))
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不能用
-
sign(A-B):因为如果不满足A
<b则返回
-
1,而不是0,这样就不能用在字段选择上了
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[A
<=B]=
sign(
1-
sign(A-B))
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[A
>B]=
1-
sign(
1-
sign(A-B))
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[A
>=B]=
sign(
1+
sign(A-B)))
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[NOTα]=
1-d [α]
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[αANDb ]=d [α]
*d [b ] (
6)
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[αOR b ]=
sign(d [α]+d
[
b
])
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例如:
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A
<B Decode(
Sign(A
-B),
-
1,
1,
0 )
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A
<=B Decode(
Sign(A
-B),
1,
0,
1 )
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A
>B Decode(
Sign(A
-B),
1,
1,
0 )
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A
>=B Decode(
Sign(A
-B),
-
1,
0,
1 )
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A
=B Decode( A, B,
1,
0 )
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A
between B
and C Decode(
Sign(A
-B),
-
1,
0,
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Decode(
Sign(A
-C),
1,
0,
1 ))
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A
is
null Decode(A,
null,
1,
0)
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A
is
not
null Decode(A,
null,
0,
1) A
in
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(B1,B2,
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,Bn) Decode(A,B1,
1,B2,
1,
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,Bn,
1,
0)
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nor LogA Decode( LogA,
0,
1,
0 )
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(
1
-
Sign(LogA))
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LogA
and LogB LogA
* LogB
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LogA
or LogB LogA
+ LogB
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LogA xor LogB Decode(
Sign(LogA),
Sign(LogB),
0,
1)
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Mod(
Sign(LogA),
Sign(LogB),
2
>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>
[
NextPage
]
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另外一个关于成绩的分析例子
SELECT
SUM(
CASE
WHEN cj
<
60
THEN
1
ELSE
0
END)
as "
not passed",
SUM(
CASE
WHEN cj
BETWEEN
60
AND
79
THEN
1
ELSE
0
END)
as
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"passed",
SUM(
CASE
WHEN cj
BETWEEN
80
AND
89
THEN
1
ELSE
0
END)
as

"good",
SUM(
CASE
WHEN cj
>=
90
THEN
1
ELSE
0
END)
as "Excellent"
FROM cjtable;
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decode用法2
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表、视图结构转化
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现有一个商品销售表sale,表结构为:
month
char(
6)
--
月份
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sell
number(
10,
2)
--
月销售金额
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现有数据为:
200001
1000
200002
1100
200003
1200
200004
1300
200005
1400
200006
1500
200007
1600
200101
1100
200202
1200
200301
1300
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想要转化为以下结构的数据:
year
char(
4)
--
年份
--
---------- ---------------------
--
-----------------
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month1
number(
10,
2)
--
1月销售金额
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month2
number(
10,
2)
--
2月销售金额
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month3
number(
10,
2)
--
3月销售金额
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month4
number(
10,
2)
--
4月销售金额
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month5
number(
10,
2)
--
5月销售金额
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month6
number(
10,
2)
--
6月销售金额
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month7
number(
10,
2)
--
7月销售金额
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month8
number(
10,
2)
--
8月销售金额
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month9
number(
10,
2)
--
9月销售金额
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month10
number(
10,
2)
--
10月销售金额
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month11
number(
10,
2)
--
11月销售金额

month12
number(
10,
2)
--
12月销售金额
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结构转化的SQL语句为:
create
or
replace
view
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v_sale(
year,month1,month2,month3,month4,month5,month6,month7,month8,month9,month10,month11,month12)
as
select
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substrb(
month,
1,
4),
sum(decode(substrb(
month,
5,
2),
'
01
',sell,
0)),
sum(decode(substrb(
month,
5,
2),
'
02
',sell,
0)),
sum(decode(substrb(
month,
5,
2),
'
03
',sell,
0)),
sum(decode(substrb(
month,
5,
2),
'
04
',sell,
0)),
sum(decode(substrb(
month,
5,
2),
'
05
',sell,
0)),
sum(decode(substrb(
month,
5,
2),
'
06
',sell,
0)),
sum(decode(substrb(
month,
5,
2),
'
07
',sell,
0)),
sum(decode(substrb(
month,
5,
2),
'
08
',sell,
0)),
sum(decode(substrb(
month,
5,
2),
'
09
',sell,
0)),
sum(decode(substrb(
month,
5,
2),
'
10
',sell,
0)),
sum(decode(substrb(
month,
5,
2),
'
11
',sell,
0)),
sum(decode(substrb(
month,
5,
2),
'
12
',sell,
0))
from sale
group
by substrb(
month,
1,
4);
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体会:要用decode
/
group
by
/
order
by
/
sign
/sum来实现不同报表的生成
>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>
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CASE应用
1
1 部门a
800 男
2
2 部门b
900 女
3
3 部门a
400 男
4
4 部门d
1400 女
5
5 部门e
1200 男
6
6 部门f
500 男
7
7 部门a
300 女
8
8 部门d
1000 男
9
9 部门d
1230 女
10
10 部门b
2000 女
11
11 部门c
2000 男
12
12 部门b
1200 男
SELECT jcxm
as 部门,
COUNT(seq)
as 人数,
SUM(
CASE SEX
WHEN
1
THEN
1
ELSE
0
END)
as 男,
SUM(
CASE SEX
WHEN
2
THEN
1
ELSE
0
END)
as 女,
SUM(
CASE
SIGN(zhi
-
800)
WHEN
-
1
THEN
1
ELSE
0
END)
as
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小于800元,
SUM((
CASE
SIGN(zhi
-
800)
*
SIGN(zhi
-
1000)
/**/
/*用*来实现<和>功能*/
WHEN
-
1
THEN
1
ELSE
0
END)
+(
CASE zhi
WHEN
800
THEN
1
ELSE
0
END))
as 从800至999,
/**/
/*注意别名不能以数字开头*/
SUM((
CASE
SIGN(zhi
-
1000)
*
SIGN(zhi
-
1200)
WHEN
-
1
THEN
1
ELSE
0
END)
+(
CASE zhi
WHEN
1000
THEN
1
ELSE
0
END))
as 从1000元至1199元,
SUM((
CASE
SIGN(zhi
-
1200)
WHEN
1
THEN
1
ELSE
0
END)
+(
CASE zhi
WHEN
1200
THEN
1
ELSE
0
END))
as 大于1200元
FroM ttt
GROUP
BY jcxm
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部门名 人数 男 女 小于800元 从800至999 从1000元至1199元 大于1200元
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部门a
3
2
1
2
1
0
0
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部门b
3
1
2
0
1
0
2
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部门c
1
1
0
0
0
0
1
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部门d
3
1
2
0
0
1
2
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部门e
1
1
0
0
0
0
1
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部门f
1
1
0
1
0
0
0
本文转自高海东博客园博客,原文链接:http://www.cnblogs.com/ghd258/archive/2006/02/10/328603.html,如需转载请自行联系原作者