判断两矩形是否相交

 1 //判断矩形是否相交
 2 bool FMath::IsRectIntersect(const FRect& rect1, const FRect& rect2)
 3 {
 4     bool bResult = true;
 5 
 6     double dWidthRectA;
 7     double dHeightRectA;
 8 
 9     double dWidthRectB;
10     double dHeightRectB;
11 
12     //方便计算，中心点坐标为实际坐标的2倍
13     CPoint centerRectA;
14     CPoint centerRectB;
15 
16     //bottom的y坐标比top的大
17     dWidthRectA = rect1.GetBottomRight().GetX() - rect1.GetTopLeft().GetX();
18     dHeightRectA = rect1.GetBottomRight().GetY() - rect1.GetTopLeft().GetY();
19 
20     dWidthRectB = fabs(rect2.GetBottomRight().GetX() - rect2.GetTopLeft().GetX());
21     dHeightRectB = fabs(rect2.GetBottomRight().GetY() - rect2.GetTopLeft().GetY()) ;
22 
23     centerRectA.x = GetDoubleInt(rect1.GetTopLeft().GetX()/2 + rect1.GetBottomRight().GetX()/2);
24     centerRectA.y = GetDoubleInt(rect1.GetTopLeft().GetY()/2 + rect1.GetBottomRight().GetY()/2);
25 
26     centerRectB.x = GetDoubleInt(rect2.GetTopLeft().GetX()/2 + rect2.GetBottomRight().GetX()/2);
27     centerRectB.y = GetDoubleInt(rect2.GetTopLeft().GetY()/2 + rect2.GetBottomRight().GetY()/2);
28 
29     
30     //判断两个矩形的中心坐标的水平和垂直距离
31     if ( (fabs(double(centerRectA.x - centerRectB.x)) <= (dWidthRectA + dWidthRectB)) 
32         && (fabs(double(centerRectA.y - centerRectB.y)) <= (dHeightRectA + dHeightRectB)) )
33     {
34         bResult =  true;
35     }
36     else
37     {
38         bResult =  false;
39     }
40 
41     return bResult;
42 
43 }

本文转自博客园知识天地的博客，原文链接：判断两矩形是否相交，如需转载请自行联系原博主。