判断两矩形是否相交

 1 //判断矩形是否相交

 2 bool FMath::IsRectIntersect(const FRect& rect1, const FRect& rect2)

 3 {

 4     bool bResult = true;

 5 

 6     double dWidthRectA;

 7     double dHeightRectA;

 8 

 9     double dWidthRectB;

10     double dHeightRectB;

11 

12     //方便计算，中心点坐标为实际坐标的2倍

13     CPoint centerRectA;

14     CPoint centerRectB;

15 

16     //bottom的y坐标比top的大

17     dWidthRectA = rect1.GetBottomRight().GetX() - rect1.GetTopLeft().GetX();

18     dHeightRectA = rect1.GetBottomRight().GetY() - rect1.GetTopLeft().GetY();

19 

20     dWidthRectB = fabs(rect2.GetBottomRight().GetX() - rect2.GetTopLeft().GetX());

21     dHeightRectB = fabs(rect2.GetBottomRight().GetY() - rect2.GetTopLeft().GetY()) ;

22 

23     centerRectA.x = GetDoubleInt(rect1.GetTopLeft().GetX()/2 + rect1.GetBottomRight().GetX()/2);

24     centerRectA.y = GetDoubleInt(rect1.GetTopLeft().GetY()/2 + rect1.GetBottomRight().GetY()/2);

25 

26     centerRectB.x = GetDoubleInt(rect2.GetTopLeft().GetX()/2 + rect2.GetBottomRight().GetX()/2);

27     centerRectB.y = GetDoubleInt(rect2.GetTopLeft().GetY()/2 + rect2.GetBottomRight().GetY()/2);

28 

29     

30     //判断两个矩形的中心坐标的水平和垂直距离

31     if ( (fabs(double(centerRectA.x - centerRectB.x)) <= (dWidthRectA + dWidthRectB)) 

32         && (fabs(double(centerRectA.y - centerRectB.y)) <= (dHeightRectA + dHeightRectB)) )

33     {

34         bResult =  true;

35     }

36     else

37     {

38         bResult =  false;

39     }

40 

41     return bResult;

42 

43 }

本文转自博客园知识天地的博客，原文链接：判断两矩形是否相交，如需转载请自行联系原博主。