递归的C#实现
1：计算数组{1,1,2,3,5,8.......} 第30位值
class Program
{
staticvoid Main(string[] args)
{
Console.WriteLine(Method1(0));
Console.WriteLine(Method1(1));
Console.WriteLine(Method1(2));
Console.WriteLine(Method1(3));
Console.WriteLine("……");
Console.WriteLine(Method1(30));
}
staticint Method1(int n)
{
if (n <2)
{
return1;
}
else
{
return Method1(n -1) + Method1(n -2);
}
}
}
2：计算1+2+3+4+...+100的值
class Program
{
staticvoid Main(string[] args)
{
Console.WriteLine(Method1(0));
Console.WriteLine(Method1(1));
Console.WriteLine(Method1(2));
Console.WriteLine(Method1(3));
Console.WriteLine("……");
Console.WriteLine(Method1(100));
}
staticint Method1(int i)
{
if (i ==0)
return0;
return Method1(i -1) + i;
}
}
3：计算1 -2 +3 +-4+ 5- 6 + 7 - 8 + 9的值
class Program
{
staticvoid Main(string[] args)
{
Console.WriteLine(Method1(0));
Console.WriteLine(Method1(1));
Console.WriteLine(Method1(2));
Console.WriteLine(Method1(3));
Console.WriteLine("……");
Console.WriteLine(Method1(100));
}
//1 -2 +3 +-4+ 5- 6 + 7 - 8 + 9
staticint Method1(int i)
{
if (i ==0)
return0;
if (i ==1)
return1;
return i%2==0? Method1(i -1) - i : Method1(i -1) + i;
}
}
4：汉诺塔
staticvoid Main(string[] args)
{
Hanoi(5, 'A', 'B', 'C');
Console.ReadLine();
}
publicstaticvoid Hanoi(int n, char A, char B, char C)
{
//汉诺塔问题
//将n个盘子从A座借助B座，移到C座
if (n ==1) Move(A, C);
else
{
Hanoi(n -1, A, C, B);
Move(A, C);
Hanoi(n -1, B, A, C);
}
}
publicstaticvoid Move(char startPlace, char endPlace)
{
Console.WriteLine("Move {0} To {1}", startPlace, endPlace);
}
本文转自最课程陆敏技博客园博客，原文链接：http://www.cnblogs.com/luminji/archive/2011/08/18/1951837.html，如需转载请自行联系原作者
