9.4 Write a method to return all subsets of a set.
LeetCode上的原题,请参见我之前的博客Subsets 子集合和Subsets II 子集合之二。
解法一:
class Solution { public: vector<vector<int> > getSubsets(vector<int> &S) { vector<vector<int> > res(1); for (int i = 0; i < S.size(); ++i) { int size = res.size(); for (int j = 0; j < size; ++j) { res.push_back(res[j]); res.back().push_back(S[i]); } } return res; } };
解法二:
class Solution { public: vector<vector<int> > getSubsets(vector<int> &S) { vector<vector<int> > res; vector<int> out; getSubsetsDFS(S, 0, out, res); return res; } void getSubsetsDFS(vector<int> &S, int pos, vector<int> &out, vector<vector<int> > &res) { res.push_back(out); for (int i = pos; i < S.size(); ++i) { out.push_back(S[i]); getSubsetsDFS(S, i + 1, out ,res); out.pop_back(); } } };
解法三:
class Solution { public: vector<vector<int> > getSubsets(vector<int> &S) { vector<vector<int> > res; int max = 1 << S.size(); for (int i = 0; i < max; ++i) { vector<int> out = convertIntToSet(S, i); res.push_back(out); } return res; } vector<int> convertIntToSet(vector<int> &S, int k) { vector<int> sub; int idx = 0; for (int i = k; i > 0; i >>= 1) { if ((i & 1) == 1) { sub.push_back(S[idx]); } ++idx; } return sub; } };
本文转自博客园Grandyang的博客,原文链接:子集合[CareerCup] 9.4 Subsets ,如需转载请自行联系原博主。