1.需求说明
有如下表数据：
ID NUM
----------- -----------
1 2
2 3
3 2
4 2
5 12
6 2
7 1
8 5
9 1
10 1
11 1
输入分组参数,比如输入 "2,5,8,10" ,实现按 ID<=2,2<ID<=5,5<ID<=8,8<ID<=10,ID>10 分组查询，要得到下面的数据：
groupdata num
---------- -----------
id<=2 5
2<id<=5 16
5<id<=8 8
8<id<=10 2
id>10 1
2.存储过程如下：
--测试数据
create table TestData(ID int,NUM int)
insert TestData select 1,2
union all select 2,3
union all select 3,2
union all select 4,2
union all select 5,12
union all select 6,2
union all select 7,1
union all select 8,5
union all select 9,1
union all select 10,1
union all select 11,1
go
create proc spgroupcol
@numlist varchar(1000)
as
set nocount on
declare @t table(id int identity,groupdata varchar(10),a int,b int)
declare @i int,@pnum varchar(10),@j int
select @i=charindex(',',@numlist)
,@pnum=left(@numlist,@i-1)
insert @t select 'id<='+@pnum,null,@pnum
while @i>=1
begin
select @numlist=substring(@numlist,@i+1,len(@numlist)-@i)
select @j=charindex(',',@numlist) ;
if @i=@j
begin
insert @t select @pnum+'<id<='+substring(@numlist,0,@i),@pnum,substring(@numlist,0,@i)
select @pnum=left(@numlist,@i-1);
end
else
begin
insert @t select @pnum+'<id<='+substring(@numlist,0,@i+1),@pnum,substring(@numlist,0,@i+1)
select @pnum=left(@numlist,@i);
end
select @i=charindex(',',@numlist) ;
end
insert @t select 'id>'+@numlist,@numlist,null
select b.groupdata,num=sum(a.num)
from TestData a,@t b
where case
when b.a is null then case when a.id<=b.b then 1 else 0 end
when b.b is null then case when a.id>b.a then 1 else 0 end
else case when a.id>b.a and a.id<=b.b then 1 else 0 end
end=1
group by b.groupdata
order by min(b.id)
go
spgroupcol '2,5,8,10'
drop table TestData
sql存储过程的单步调试要在Vs2008中，服务器管理器中连接上数据库，找到存储过程右键单步调试。
本文转自生鱼片博客园博客，原文链接：http://www.cnblogs.com/carysun/archive/2009/09/12/groupcolumnscope.html，如需转载请自行联系原作者
